c++ - 将新节点添加到具有两个类的链表

Question

当尝试将新的 Node 添加到喜欢的列表时，它给我一个 Segmentation fault。谁能告诉我 addBook() 函数的实现有什么问题。我不确定是函数的实现有问题，还是我声明类的方式有问题。

class Reservation {
        public:

    int getID();
    string getResevNum();

    void setId(int x);
    void setReseNum(string y);

    private:
        int ID;
        string reservedNumber;
};

class ReservationCollection {
    public:
    ReservationCollection();
    ~ReservationCollection();

    int getUserId(int &id);
    string getUserBook(string &bookCall);

    void findReservation();
    void display();

    void addBook(int id, string book);
    void RemoveBook();
    void ShutDown();

    private:
        struct Node {
            Reservation *data;
            Node *next;
            };
        Node *head;
 };

ReservationCollection::ReservationCollection() {
    Node *head = new Node;
    head->next = NULL;  
}

ReservationCollection::~ReservationCollection() {
}

void ReservationCollection::addBook(int id, string book){
    Node *tmp = new Node;

    tmp->data->setId(id);
    tmp->data->setReseNum(book);
    tmp->next = head->next;
    head->next = tmp;
    cout <<"Good\n";
}

int Reservation::getID(){
    return ID;
}

string Reservation::getResevNum(){
    return reservedNumber;
}
void Reservation::setId(int x){
    ID = x;
}

void Reservation::setReseNum(string y){
    reservedNumber = y;
}

int ReservationCollection::getUserId(int &id){
    cout << "Enter Id number " << endl;
    cin >> id;
    return id;
}

string ReservationCollection::getUserBook(string &bookCall){
    cout << "Enter book reservatin " << endl;
    cin >> bookCall;
    return bookCall;
}

int main()
{
    int ID;
    string BookNum;
    char cmd;

    do {
        cout << "Enter command: ";
        cin >> cmd;

        ReservationCollection list;
        if (cmd == 'A' || cmd == 'a'){

            list.getUserId(ID);
            list.getUserBook(BookNum);

            list.addBook(ID, BookNum);
        }
        else if (cmd == 'S' || cmd == 's'){
            cout << " list";
        }
    } while (cmd != 'Q' || cmd == 'q');

}

Answer 1

希望我能评论一下:

Node *tmp = new Node; 行的所有实例都应显示为 Node *tmp = new Node();