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javascript - AngularJS:正确定义回调?

转载 作者:行者123 更新时间:2023-11-30 05:31:54 25 4
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我正在尝试打印一个对象列表,显示它们的名称以及它与用户位置之间的距离。我确实通过 GET 检索数据并根据纬度和经度计算距离。但是,我的范围数组的长度仍然为 0。我猜我的回调架构有问题,但我似乎无法弄清楚。

Controller :

angular.module('ionicApp', ['ionic']).controller('objectCtrl', function($scope, $http) {
$scope.objects = [];
$http.get('http://url.com/getobjects.php').then(function (resp) {
for (var i = 0; i < resp.data.length; i++) {
getDistance(resp.data[i].lat, resp.data[i].lng, (function(index){
return function(dist){
$scope.objects[index] = {
name: resp.data[index].name,
distance: dist
};
}
})(i));
}
}, function (err) {
console.error('ERR', err);
alert("error");
});

获取距离:

function getDistance(lat2, lon2, callback) {
navigator.geolocation.getCurrentPosition(function onSuccess(position) {
var lat1 = position.coords.latitude;
var lon1 = position.coords.longitude;
var radlat1 = Math.PI * lat1 / 180;
var radlat2 = Math.PI * lat2 / 180;
var radlon1 = Math.PI * lon1 / 180;
var radlon2 = Math.PI * lon2 / 180;
var theta = lon1 - lon2;
var radtheta = Math.PI * theta / 180;
var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
dist = Math.acos(dist);
dist = dist * 180 / Math.PI;
dist = dist * 60 * 1.1515;
dist = dist * 1.609344;
callback(dist);
}, function onError(error) {
alert("no location found:"+ error);
});
}

知道我的代码有什么问题吗?谢谢。

最佳答案

看起来 getDistance 回调出现在 $digest 循环之外。所以你应该尝试手动启动它:

$scope.objects[index] = {
name: resp.data[index].name,
distance: dist
};
$scope.$apply();

或者使用$timeout服务:

getDistance(resp.data[i].lat, resp.data[i].lng, (function (index) {
return function (dist) {
$timeout(function() {
$scope.objects[index] = {
name: resp.data[index].name,
distance: dist
};
});
}
})(i));

关于javascript - AngularJS:正确定义回调?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26424376/

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