java - 如何形成json对象

Question

我想使用 JsonObect 和 JsonArray 转换以下 JSON，但无法执行此操作。

{
  "query": {
    "bool": {
      "must": [
        {
          "match": {
            "customer.partnerName": "Synapse"
          }
        },
        {
          "range": {
            "customer.billing.chargeAmount": {
              "gte": 1,
              "lte": 100
            }
          }
        }
      ],
      "filter": [
        {
          "match": {
            "customer.configId": 15
          }
        }
      ]
    }
  }
}

我尝试使用JsonObject但无法实现结果。

Answer 1

这只是将 json 字符串简单复制/粘贴到 AndroidStudio 中，它会自动分割字符串并添加转义斜杠.. 它看起来很糟糕，但你编写的语法完全没问题..

    String jsonString = " {\n" +
            "                        \"query\": {\n" +
            "                        \"bool\": {\n" +
            "                            \"must\": [\n" +
            "                                    {\"match\": \n" +
            "            { \"customer.partnerName\":   \"Synapse\"  }},\n" +
            "\n" +
            "                                    {\n" +
            "\"range\" : \n" +
            "{\n" +
            "                                        \"customer.billing.chargeAmount\" : {\n" +
            "                                            \"gte\" : 1,\n" +
            "                                            \"lte\" : 100\n" +
            "                                        }\n" +
            "                                    }}\n" +
            "                            ],\n" +
            "                            \"filter\": [\n" +
            "                                    { \"match\":  { \"customer.configId\": 15 }}\n" +
            "                            ]\n" +
            "                        }\n" +
            "                    }\n" +
            "                    }";

    // HERE BEAUTIFIED
    /*jsonString = "{\"query\":{\"bool\":{\"must\":[{\"match\":{\"customer.partnerName\":\"Synapse\"}},{\"range\":{\"customer.billing.chargeAmount\":{\"gte\":1,\"lte\":100}}}],\"filter\":[{\"match\":{\"customer.configId\":15}}]}}}";
     */

    try {
        JSONObject object = new JSONObject(jsonString);

        // NO ERRORS, OBJECT CREATED IN MY CASE
    } catch (JSONException e) {
        e.printStackTrace();
    }

您拥有的第二个选项是以编程方式创建对象、内部对象和数组..就像这样..

    try {

        JSONObject jsonObject = new JSONObject();


        JSONObject query = new JSONObject();
        jsonObject.put("query", query);


        JSONObject bool = new JSONObject();
        query.put("bool", bool);


        JSONArray must = new JSONArray();
        bool.put("must", must);


        JSONObject matchWrap = new JSONObject();

        JSONObject match = new JSONObject();
        match.put("customer.partnerName", "Synapse");

        matchWrap.put("match", match);

        must.put(matchWrap);


        JSONObject rangeWrap = new JSONObject();

        JSONObject range = new JSONObject();

        JSONObject customerBillingChargeAmount = new JSONObject();
        customerBillingChargeAmount.put("gte", 1);
        customerBillingChargeAmount.put("lte", 100);

        range.put("customer.billing.chargeAmount", customerBillingChargeAmount);

        rangeWrap.put("range", range);


        must.put(rangeWrap);




        JSONArray filter = new JSONArray();
        bool.put("filter", filter);


        JSONObject match2Wrap = new JSONObject();

        JSONObject match2 = new JSONObject();
        match2.put("customer.configId", 15);

        match2Wrap.put("match", match2);


        filter.put(match2Wrap);



        String jsonString2 = jsonObject.toString();

        // HERE THE SAME JSON STRING AS YOUR INPUT

    } catch (JSONException e) {
        e.printStackTrace();
    }

当删除空格、制表符、换行符等时，这会产生与输入字符串相同的结果。