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c++ - 合并排序和快速排序 C++ 的工具箱(有错误的代码)

转载 作者:行者123 更新时间:2023-11-30 05:27:43 25 4
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大家好,我找不到错误。这是我的代码:

#include <iostream>
using namespace std;

int a[20], n, lb, loc, ub, left, right, temp, temp1;

void quicksort(int[10],int,int);

int pivot(int[],int,int);

void merge(int *,int, int , int );

void mergesort(int *a, int low, int high)
{
int mid;
if (low < high)
{
mid=(low+high)/2;
mergesort(a,low,mid);
mergesort(a,mid+1,high);
merge(a,low,high,mid);
}
return;
}

void merge(int *a, int low, int high, int mid)
{
int i, j, k, c[50];
i = low;
k = low;
j = mid + 1;

while (i <= mid && j <= high)
{
if (a[i] < a[j])
{
c[k] = a[i];
k++;
i++;
}
else
{
c[k] = a[j];
k++;
j++;
}
}
while (i <= mid)
{
c[k] = a[i];
k++;
i++;
}
while (j <= high)
{
c[k] = a[j];
k++;
j++;
}
for (i = low; i < k; i++)
{
a[i] = c[i];
}
}
int main()
{
int opt;
cout << "QuickSort & MergeSort Toolbox: " << endl;
do
{
int opt;
cout << "1. MergeSort" << endl;
cout << "2. QuickSort" << endl;
cout << "enter option: ";
cin >> opt;

switch(opt)
{
case 1:
{
cout << "MERGE SORT" << endl;
int a[20], i, b[20];
cout<<"Enter the elements\n";
for (i = 0; i < 5; i++)
{
cin>>a[i];
}
mergesort(a, 0, 4);
cout<<"Sorted array\n";
for (i = 0; i < 5; i++)
{
cout<<a[i];
}
cout<<"Enter the elements\n";
for (i = 0; i < 5; i++)
{
cin>>b[i];
}
mergesort(b, 0, 4);
cout<<"Sorted array\n";
for (i = 0; i < 5; i++)
{
cout<<b[i];
}
}

case 2:
{
cout<<"Enter size of array";
cin>>n;
cout<<"Enter Array Elements ";
for(int i=0;i<n;i++)
{
cin>>a[i];
}
quicksort(a,0,n-1);
for(int z=0;z<n;z++)
{
cout<<" "<<a[z];
}
return 0;
}

default:
{
cout << "Invalid Input" << endl;
}
}
}while(opt != -1);

void quicksort(int a[], int lb, int ub)
{
int p;

if(lb<ub)
{
p=pivot(a,lb,ub);
quicksort(a,lb,p-1);
quicksort(a,p+1,ub);
}
}

int pivot( int a[],int lb,int ub )
{
for(int z=0;z<n;z++)
{
cout<<" "<<a[z];
}

cout<<endl;

left =lb;
right = ub;
loc =lb;

cout<<"Right Side is:- "<<right;
cout<<"\tLocation is:-"<<loc;
cout<<"Left Side is:- "<<left;
cout<<"Now Right Side is: \n";

while((a[loc]<=a[right]) && (loc!=right))
{
right=right-1;
}

if(loc==right)
{
return loc;
}

temp=a[loc];
a[loc]=a[right];
a[right]=temp;
loc=right;
cout<<"Now Left Side is: \n";

while((a[left]<=a[loc]) && (loc!=left))
{
left=left+1;
}

if(loc==left)
{
return loc;
}

temp1=a[loc];
a[loc]=a[left];
a[left]=temp1;
loc=left;
}

我想更正那个错误,但我能找到它。非常欢迎任何帮助或提示。终端显示这是一个遗漏的括号,但我看到了所有括号。

最佳答案

在此处在线缩进您的代码。然后,正如编译器所说,转到第 131 行并注意 main 没有右大括号。添加一个,例如这样:

    ...
}while(opt != -1);
return 0;
}

这将解决这个问题,但代码也会出现其他错误,但我会把有趣的部分留给你。

我有一个 Quicksort (C++) 的例子,这可能会派上用场。

关于c++ - 合并排序和快速排序 C++ 的工具箱(有错误的代码),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37116814/

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