Java 8 : Sonar compliant Server Socket

Question

下面是我的服务器套接字线程的run()，它将作为Executors.newWorkStealingPool().submit(() -> mainServer.run());运行code> 并接受客户端连接。它运行良好，但Sonar提示它是Bug类型的循环不应该是无限的(squid:S2189)

    class MainServer {
    private final ServerSocket serverSocket;    
    private final boolean checkClientCerts;
    private static final org.slf4j.Logger LOG = LoggerFactory.getLogger(MainServer.class.getName());
    private final int threadPoolSize;
    private boolean running;
    private ExecutorService executorService;    

 MainServer(int port, boolean checkClientCerts, int threadPoolSize, InetAddress bindAddress) throws IOException {

        LOG.debug("Locating server socket factory for SSL...");
        SSLServerSocketFactory factory = (SSLServerSocketFactory) SSLServerSocketFactory.getDefault();
        LOG.debug("Creating a server socket on port " + port);
        SSLServerSocket serverSocket = (SSLServerSocket) factory.createServerSocket(port, 0, bindAddress);        
        this.checkClientCerts = checkClientCerts;
        this.threadPoolSize = threadPoolSize;
    }

    void run() {
        running = true;
        DefaultThreadFactory threadFactory = new DefaultThreadFactory("SSLHandshake");
        executorService = new ShutdownThreadPoolExecutor(threadPoolSize,threadFactory);

        while (running) {
            Socket clientSocket;

            try {
                clientSocket = serverSocket.accept();
                MainServerHandshakeThread handshakeThread = new MainServerHandshakeThread(clientSocket, this);                
                executorService.submit(handshakeThread);

            } catch (IOException ex) {
                LOG.error("Error accepting connection",ex);
            }

        }
    }

    public void shutdown() {
        LOG.info("Stopping main server...");
        running = false;
        try {
            if (serverSocket!=null) {
                serverSocket.close();
            }
        } catch(IOException ex) {
            LOG.debug("Failed to close socket",ex);
        }

        executorService.shutdown();
        try {
            if (!executorService.awaitTermination(500, TimeUnit.MILLISECONDS)) {
                executorService.shutdownNow();
            } 
        } catch (InterruptedException e) {
            executorService.shutdownNow();
        }             
        LOG.info("Main server stopped...");
    }
}

有人可以帮助我如何优化上述代码块以消除声纳投诉吗？

Answer 1

将您的正在运行标记为 volatile 。

volatile 将变量可见标记为可被其他线程更改¹。这意味着优化器(或代码分析器，如 SonarQube)不能假设其他线程不修改此类变量。在您的示例中，这两个都可以假设正在运行永远不会改变，从而将您的代码标记为具有无限循环。类似的例子可以找到in this answer .

如果变量可以被其他线程访问和修改，您应该将它们标记为 volatile 。

<小时/>

¹由user207421更正。