java - 代码仅在一种情况下不断跳过一行输入

Question

我一直在为 TicTacToe 游戏编写代码，但我陷入了一个循环，当玩家为已标记的位置输入输入时，它会提示用户再次输入。问题是，这只是代码跳过一行输入的情况。我应该做什么？

   Scanner input = new Scanner(System.in);
   boolean bool = false;

   System.out.println("It is the player's move");
   System.out.println("Give me your best move!");

   while(!bool){
           String Answer = input.nextLine();

           Answer = validateUserResponse(Answer);

           int move = Integer.parseInt(Answer);

           if(validatePlayerMove(move))
           {
               if(checkPositionAvailability(move))
               {
                   board[move] = 'H'; //make 'H' for player move
                   bool = true;
               }
               else
               {
                   System.out.println("Position not available.\nMake a different choice.");
                   Answer = input.nextLine();
               }
           }
           else
           {
               System.out.println("Invalid entry!");
               Answer = input.nextLine();
           }
       }

Answer 1

所以我已经弄清楚了，我在 boolean 循环中提示了两个输入，所以我只需将第一个输入移到循环之外。

Scanner input = new Scanner(System.in);
       boolean bool = false;

       System.out.println("It is the player's move");
       System.out.println("Give me your best move!");

       String Answer = input.nextLine();

       while(!bool){

           Answer = validateUserResponse(Answer);

           int move = Integer.parseInt(Answer);

           if(validatePlayerMove(move))
           {
               if(checkPositionAvailability(move))
               {
                   board[move] = 'H'; //make 'H' for player move
                   bool = true;
               }
               else
               {
                   System.out.println("Position not available.\nMake a different choice.");
                   Answer = input.nextLine();
               }
           }
           else
           {
               System.out.println("Invalid entry!");
               Answer = input.nextLine();
           }
       }