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c++ - 可变参数模板、递归、非类型名参数

转载 作者:行者123 更新时间:2023-11-30 05:21:00 25 4
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我正在尝试使用非类型名称参数构建一些简单的可变参数模板:

  #include <iostream>

void myf()
{
}

template<int Arg1, int ... Args> void myf()
{
std::cout << Arg1 << ", ";
myf<Args...>();
}

int main()
{
myf<1,2,3,4,5>();
}

尝试编译并得到:

test.cpp: In instantiation of ‘void myf() [with int Arg1 = 5; int ...Args = {}]’:
test.cpp:10:18: recursively required from ‘void myf() [with int Arg1 = 2; int ...Args = {3, 4, 5}]’
test.cpp:10:18: required from ‘void myf() [with int Arg1 = 1; int ...Args = {2, 3, 4, 5}]’
test.cpp:15:20: required from here
test.cpp:10:18: error: no matching function for call to ‘myf()’
myf<Args...>();
^
test.cpp:10:18: note: candidate is:
test.cpp:7:39: note: template<int Arg1, int ...Args> void myf()
template<int Arg1, int ... Args> void myf()
^
test.cpp:7:39: note: template argument deduction/substitution failed:
test.cpp:10:18: note: couldn't deduce template parameter ‘Arg1’
myf<Args...>();

看来,递归终止不起作用。终止非类型名可变参数模板递归的正确方法是什么?

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