C++ 代码无法编译

Question

代码无法编译。我不明白错误是什么，请帮助)

#include <iostream>
#include <fstream>

class Record{
    std::string product_name;
    std::string product_category;
    int price;
    int amount;
public:
Record(std::string newName, std::string newCategory, int newPrice, int newAmount){
    product_name=newName;
    product_category=newCategory;
    price=newPrice;
    amount=newAmount;
}

    std::string getName(){
        return product_name;
    }
    std::string getCategory(){
        return product_category;
    }
    int getPrice(){
        return price;
    }
    int getAmount(){
        return amount;
    }
    void setName(std::string newName){
        product_name=newName;
    }
    void setCategory(std::string newCategory){
        product_category=newCategory;
    }
    void setPrice(int newPrice){
        price=newPrice;
    }
    void setAmount(int newAmount){
        amount=newAmount;
    }
};

int main(){
    Record r1;
    r1.setName("beer");
    r1.setCategory("alcohol");
    r1.setPrice(12);
    r1.setAmount(32);
    Record r2("carrot", "vegetables", 123, 1932);
    std::cout<<r1.getName()<<" "<<r1.getCategory()<<" "<<r1.getPrice()<<" "<<r1.getAmount()<< std::endl;
    std::cout<<r2.getName()<<" "<<r2.getCategory()<<" "<<r2.getPrice()<<" "<<r2.getAmount()<< std::endl;
    Record r3[2];
    std::string a;
    float b;
    unsigned int c;
    for(unsigned int i=0; i<2; ++i){
        std::cout<<"input name: ";
        std::cin>>a;
        r3[i].setName(a);
        std::cout<<"input category: ";
        std::cin>>a;
        r3[i].setCategory(a);
        std::cout<<"input price: ";
        std::cin>>b;
        r3[i].setPrice(b);
        std::cout<<"input amount: ";
        std::cin>>c;
        r3[i].setAmount(c);
    }
    for(unsigned int i=0; i<2; ++i){
        std::cout<<r3[i].getName()<<" "<<r3[i].getCategory()<<" "<<r3[i].getPrice()<<" "<<r3[i].getAmount()<< std::endl;

    }

    return 0;

}

Error text: g++ -Wall -c "main.cpp" ( /media/ad/4GB-NTFS/prog/laba2) main.cpp: In function ‘int main()’: main.cpp:46:12: error: no matching function for call to ‘Record::Record()’ Record r1; ^ main.cpp:12:1: note: candidate: Record::Record(std::__cxx11::string, std::__cxx11::string, int, int) Record(std::string newName, std::string newCategory, int newPrice, int newAmount){ ^ main.cpp:12:1: note: candidate expects 4 arguments, 0 provided main.cpp:6:7: note: candidate: Record::Record(const Record&) class Record{ ^ main.cpp:6:7: note: candidate expects 1 argument, 0 provided main.cpp:54:16: error: no matching function for call to ‘Record::Record()’ Record r3[2]; ^ main.cpp:12:1: note: candidate: Record::Record(std::__cxx11::string, std::__cxx11::string, int, int) Record(std::string newName, std::string newCategory, int newPrice, int newAmount){ ^ main.cpp:12:1: note: candidate expects 4 arguments, 0 provided main.cpp:6:7: note: candidate: Record::Record(const Record&) class Record{ ^ main.cpp:6:7: note: candidate expects 1 argument, 0 provided

Answer 1

您的类没有默认构造函数。所以当你说:

   Record r1;

编译器不知道如何创建r1 对象。您要么需要在创建 r 时提供所有参数:

  Record r1( "foo", "bar", 1, 2 );

或者更好地完全重新考虑您的程序设计。