android - 手动启动 Firebase 服务

Question

我正在创建一个包含 FireBase 消息服务的应用程序。
我在 list 中添加了服务:

 <service android:name="xxx.xxx.MyFirebaseInstanceIdService">
            <intent-filter>
                <action android:name="com.google.firebase.INSTANCE_ID_EVENT"/>
            </intent-filter>
        </service>

 <service android:name="xxx.xxx.MyFireBaseMessagingService">
            <intent-filter>
                <action android:name="com.google.firebase.MESSAGING_EVENT" />
            </intent-filter>
        </service>

我有两个用于获取 token 和 firebase 消息的类:

public class MyFirebaseInstanceIdService extends FirebaseInstanceIdService {

    @Override
    public void onTokenRefresh() {
        super.onTokenRefresh();
        String recent_token = FirebaseInstanceId.getInstance().getToken();
        SharedPreferences sp = getSharedPreferences("mypref", 0);
        SharedPreferences.Editor editor = sp.edit();
        editor.putString("token", recent_token);
        editor.apply();
    }
}

和消息类:

public class MyFireBaseMessagingService extends FirebaseMessagingService {


    @Override
    public void onMessageReceived(final RemoteMessage remoteMessage) {
        super.onMessageReceived(remoteMessage);
        Intent intent = new Intent(MyFireBaseMessagingService.this, AdvCreateActivity.class);
        intent.putExtra("mode","notification");
        intent.putExtra("text",remoteMessage.getNotification().getBody());
        intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        PendingIntent pendingIntent = PendingIntent.getActivity(MyFireBaseMessagingService.this,0,intent,PendingIntent.FLAG_UPDATE_CURRENT);
        NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(MyFireBaseMessagingService.this);
        notificationBuilder.setContentTitle(remoteMessage.getNotification().getTitle());
        notificationBuilder.setContentText(remoteMessage.getNotification().getBody());
        notificationBuilder.setAutoCancel(true);
        notificationBuilder.setSmallIcon(R.mipmap.ic_launcher);
        notificationBuilder.setContentIntent(pendingIntent);
        NotificationManager notificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        notificationManager.notify(0,notificationBuilder.build());
    }
}

当应用程序启动时，firebase 服务会自动启动。如果设备没有互联网连接，那么我就无法收到 token 。如果我打开数据或 wifi，firebase 将不会发送 token !
我的问题是:如何在应用程序启动后手动启动 firebase 服务？ (我不希望 firebase 服务在启动应用程序时启动!!!)

Answer 1

请在任何您想获取您的 fcm id 的地方调用以下方法。

try {
        String refreshedToken = FirebaseInstanceId.getInstance().getToken();
        Log.d("Firbase id login", "Refreshed token: " + refreshedToken);
    } catch (Exception e) {
        e.printStackTrace();
    }