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c++ - 凯撒密码删除数据

转载 作者:行者123 更新时间:2023-11-30 05:08:53 24 4
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我想知道是否有人可以帮助我解决我的代码问题。它似乎一切正常,但是当我运行它时,它运行到一半就开始删除我的数据,即使我从来没有调用任何东西来删除它。

例如我的文件来自:

=======================
Rotated by 11 positions
=======================
Lnwypeyw lala sqz xa na lnwypeyw eb pdau sqz pwa w eppa
na pea bn znawec.
-- F. L. IyAru**
to
=======================
Rotated by 12 positions
=======================
Moxzqzx mbmb tra yb ob moxzqzx c qebv tra qxb x qqb
ob qb co aobxd.
-- G. M. JzBsv

这是我的代码,我试过几次它在逻辑上都是有意义的,但不知道它会丢失数据。

#include <iostream>
#include <cctype>
#include <fstream>

using namespace std;

bool isUpper(char character){

//this will test and see if it's upper or lowercase
bool upper;

if(character>= 'A' && character <= 'Z'){
upper=true;
}
else {
upper= false;
}

return upper;
}

bool isLower(char character){

//this will test and see if it's upper or lowercase
bool lower;

if(character >= 'a' && character <= 'z'){
lower=true;
}

else {
lower= false;
}

return lower;
}

//Actual function that will rotate the character
char rotate(char character, int offset) {

char next_letter;

//Changes it if it's a lower case
if (isLower(character)) {

next_letter = character + offset;

if (next_letter > 'z'){
next_letter = (next_letter - 26);
return next_letter;
}

return next_letter;
}

else if(isUpper(character)) {

next_letter = character + offset;

if (next_letter > 'Z'){
next_letter = (next_letter - 26);
return next_letter;
}

return next_letter;
}

else {
return character;
}
}


int main() {

//variables for program
char character = 'a';
int offset = 0;

while(offset < 26){

//opens the file
ifstream fin;
fin.open("secretMessage.txt");

if(!fin.good()) {
cout << "Please check your file name!!!";
return 0;
}

//report for reading
cout << "=======================" << endl
<< "Rotated by " << offset << " positions" << endl
<< "=======================" << endl;

//Reads until it's at the end of the file
while ((! fin.eof())){
character = fin.get();

cout << rotate(character,offset);

}

//makes it run 26 times
++offset;
fin.close();
cout << endl << endl;
}
//Closes the file output.
return 0;
}

最佳答案

在这个逻辑中:

    if (next_letter > 'z') {
next_letter = (next_letter - 26);
return next_letter;
}

你没有想到如果 char 被签名会发生什么。测试一下:

assert(rotate('z', 0) == 'z');
assert(rotate('z', 1) == 'a');
assert(rotate('z', 2) == 'b');
assert(rotate('z', 3) == 'c');
assert(rotate('z', 4) == 'd');
assert(rotate('z', 5) == 'e');

到目前为止还不错,但是现在:

assert(rotate('z', 6) == 'f'); // WHOOPS

Ascii 'z'+5 是 127,'z'+6 是 128。但是,z+=6 结果为负,所以检查 > 'z'失败。

建议的简化:

bool isUpper(char ch) { return (ch >= 'A' && ch <= 'Z'); }
bool isLower(char ch) { return (ch >= 'a' && ch <= 'z'); }

// Actual function that will rotate the character
char rotate(char ch, int offset) {
if (isLower(ch)) return (ch - 'a' + offset) % 26 + 'a';
if (isUpper(ch)) return (ch - 'A' + offset) % 26 + 'A';
return ch;
}

由于您包括 <cctype> , 你不妨使用 std::islowerstd::isupper .

Live On Coliru

#include <cctype>
#include <fstream>
#include <iostream>
#include <algorithm>

// Actual function that will rotate the character
char rotate(char ch, int offset) {
if (std::islower(ch)) return (ch - 'a' + offset) % 26 + 'a';
if (std::isupper(ch)) return (ch - 'A' + offset) % 26 + 'A';
return ch;
}

std::string readFile(std::string const& fname) {
std::ifstream fin;
fin.exceptions(std::ios::failbit);
fin.open(fname);
return { std::istreambuf_iterator<char>(fin), {} };
}

int main() {

auto const original = readFile("main.cpp");

// makes it run 26 times
for (int offset = 0; offset < 26; ++offset) {

std::cout
<< "\n"
<< "=======================\n"
<< "Rotated by " << offset << " positions\n"
<< "=======================\n";

// Reads until it's at the end of the file
std::transform(
original.begin(), original.end(),
std::ostreambuf_iterator<char>(std::cout),
[offset](char ch) { return rotate(ch, offset); });
}
}

奖金

实际上,您可以通过原地按 1 旋转 26 次来避免 main 中的复杂性:

Live On Coliru

auto text = readFile("main.cpp");

for (int offset = 0; offset < 26; ++offset) {
std::cout
<< "\n"
<< "=======================\n"
<< "Rotated by " << offset << " positions\n"
<< "=======================\n";

std::cout << text;
for (auto& ch : text) ch = rotate(ch, 1);
}

关于c++ - 凯撒密码删除数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46534881/

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