c++ - 在 C++ 中使用二维数组

Question

我正在处理一个包含 9 个和 9 个元素的二维数组，grid[9][9]，我需要检查特定元素是否相等，如果相等，则将第一个数组标记为第二个数组。

bool gridWon(int n){
    if ( grid[n][0] != 0 && grid[n][0] == grid[n][1] && grid[n][0] == grid[n][2]){
        return true;
    } else if ( grid[n][3] != 0 && grid[n][3] == grid[n][4] && grid[n][5] == grid[n][3]){
        return true;
    } else if ( grid[n][6] != 0 && grid[n][6] == grid[n][7] && grid[n][8] == grid[n][6]){
        return true;
    } else if ( grid[n][0] != 0 && grid[n][0] == grid[n][4] && grid[n][8] == grid[n][0]){
        return true;
    } else if ( grid[n][2] != 0 && grid[n][2] == grid[n][4] && grid[n][6] == grid[n][2]){
        return true;
    } else if ( grid[n][0] != 0 && grid[n][0] == grid[n][3] && grid[n][6] == grid[n][0]){
        return true;
    } else if ( grid[n][1] != 0 && grid[n][1] == grid[n][4] && grid[n][7] == grid[n][1]){
        return true;
    } else if ( grid[n][2] != 0 && grid[n][2] == grid[n][5] && grid[n][8] == grid[n][2]){
        return true;
    } else
        return false;
}

我怎样才能写得更优雅，我怎样才能标记 grid[n][] 以便稍后比较它们？

例子:

if grid[1][] returns true then I need to know later to compare if grid[1][] == grid[2][] == true

Answer 1

返回逻辑运算的结果会不会更好:

bool gridWon(int n){
 return (grid[n][0] != 0 && grid[n][0] == grid[n][1] && grid[n][0] == grid[n][2]) ||
  (grid[n][3] != 0 && grid[n][3] == grid[n][4] && grid[n][5] == grid[n][3]) ||
  (grid[n][6] != 0 && grid[n][6] == grid[n][7] && grid[n][8] == grid[n][6]) ||
  (grid[n][0] != 0 && grid[n][0] == grid[n][4] && grid[n][8] == grid[n][0]) ||
  (grid[n][2] != 0 && grid[n][2] == grid[n][4] && grid[n][6] == grid[n][2]) ||
  (grid[n][0] != 0 && grid[n][0] == grid[n][3] && grid[n][6] == grid[n][0]) ||
  (grid[n][1] != 0 && grid[n][1] == grid[n][4] && grid[n][7] == grid[n][1]) ||
  (grid[n][2] != 0 && grid[n][2] == grid[n][5] && grid[n][8] == grid[n][2]);
}