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Java正则表达式从字符串中提取测量值

转载 作者:行者123 更新时间:2023-11-30 05:03:20 25 4
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我正在尝试从简短的、不一致的产品描述中提取数据,以便部分自动化地为我公司的在线商店制作产品网页。不幸的是,描述并不统一。感谢这个网站,我对正则表达式有了足够的了解,可以对其进行公平的尝试。

在产品测量方法中,这里是一个失败的测试。

w。本产品尺寸为 68 厘米 x 22 厘米 x 73 厘米 --
长度:68 厘米宽度:73 厘米高度:

但是这个非常相似的测试并没有失败。为什么?

x。本产品尺寸为 68 厘米 x 22 厘米 x 73 厘米 --
长度:68 厘米宽度:22 厘米高度:73 厘米

这是测试类。作为一个正则表达式菜鸟,我确信我做得不是很有效,所以关于效率的建议会很棒。如果您能想到任何其他失败的测试用例,请告诉我。

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class TesterClass {
public static final String[] testArray =
{
"a. Dynabrade 4\" Discs 34-333-102",
"b. Mercer 4 Inch Discs",
"c. Mercer 4in Discs",
"d. Carbo CleanAir 6\' Vacuum Tube Attachment",
"e. 4 feet",
"f. 4 Ft",
"g. 4 foot",
"h. Carborundum 2-3/4\" Tape 4 yd Roll 97580",
"i. I want 5 Inches and later 6 Feet",
"j. I don't want this one pyrex 9",
"k. This is 4 Inches x 5 Inches x 6 Feet in Size",
"l. This one is 6 x 5 Inches",
"m. This is 4\" x 5\" x 6\' in size",
"n. Something 4-3/4\" Long",
"o. I don't want 9 xtreme things",
"p. I don't want 9 men",
"q. 674m",
"r. 4 Inches",
"s. 5x8",
"t. P58\"",
"u. 5 x 7",
"v. 6 yards",
"w. This product is 68 cm by 22 cm by 73 cm",
"x. This product is 68 cm x 22 cm x 73 cm"
};
public static final String[] FIELDNAMES = {"Length: ","Width: ","Height: "};

public static final String
MEASURE = "(f(ee)?(oo)?t|in(ch)?(es)?|y(ar)?d(s)?|cm|m|meter(s)?|\"|\')",
MAYBE_MEASURE = MEASURE + "?",
NUMBER = "([0-9\\-/]+)",
X = "[(x)(by)]",
SPACE = "\\s",
MAYBE_SPACE = "\\s?",
SPACE_OR_END = "(\\s|$)",
START = "^",
END = "$",
TAB = "\t";

public static final Pattern
regular = Pattern.compile(NUMBER + MAYBE_SPACE + MEASURE + SPACE_OR_END, Pattern.CASE_INSENSITIVE),
lengthXwidth = Pattern.compile(NUMBER + MAYBE_SPACE + MAYBE_MEASURE + MAYBE_SPACE + X + MAYBE_SPACE + NUMBER + MAYBE_MEASURE, Pattern.CASE_INSENSITIVE),
beforeX = Pattern.compile(NUMBER + MAYBE_SPACE + MAYBE_MEASURE + MAYBE_SPACE + END, Pattern.CASE_INSENSITIVE),
afterX = Pattern.compile(START + MAYBE_SPACE + NUMBER + MAYBE_SPACE + MAYBE_MEASURE, Pattern.CASE_INSENSITIVE),
measure = Pattern.compile(MAYBE_SPACE + MEASURE, Pattern.CASE_INSENSITIVE);


public static void main(String[] args)
{
for (String testString:testArray)
{
String[] fields = {"","",""};
int match = 0;
Matcher lengthXwidthMatcher = lengthXwidth.matcher(testString);
Matcher regularMatcher = regular.matcher(testString);

if (lengthXwidthMatcher.find())
{
String[] split = testString.split(X);
for (int i = 0; i<split.length; i++)
{
Matcher beforeXMatcher = beforeX.matcher(split[i]);
Matcher afterXMatcher = afterX.matcher(split[i]);
if (beforeXMatcher.find() && match==0)
{
fields[0] = beforeXMatcher.group();
match++;
}
if (afterXMatcher.find())
{
if (match==1)
{
fields[1] = afterXMatcher.group();
match++;
}
else if (match==2)
{
fields[2] = afterXMatcher.group();
match++;
}
}
}
Matcher lengthHasMeasure = measure.matcher(fields[0]);
Matcher widthHasMeasure = measure.matcher(fields[1]);
Matcher heightHasMeasure = measure.matcher(fields[2]);
if (heightHasMeasure.find()==true)
{
if (lengthHasMeasure.find()==false)
{
fields[0] = fields[0] + heightHasMeasure.group();
}
if (widthHasMeasure.find()==false)
{
fields[1] = fields[1] + heightHasMeasure.group();
}
}
else if (widthHasMeasure.find()==true)
{
if (lengthHasMeasure.find()==false)
{
fields[0] = fields[0] + widthHasMeasure.group();
}
}
}
else if(regularMatcher.find())
{
fields[0] = regularMatcher.group();
match++;
while (regularMatcher.find() && match<3)
{
fields[match] = regularMatcher.group();
}
}

System.out.println(testString + " -- " + TAB + FIELDNAMES[0] + fields[0] + TAB + FIELDNAMES[1] + fields[1] + TAB + FIELDNAMES[2] + fields[2]);
}
}
}

最佳答案

看起来您的 X 产品被指定为字符类,而不是交替。尝试:

X = "(x|by)"

关于Java正则表达式从字符串中提取测量值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5924090/

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