android - Flutter:Firebase Phone Auth 未授权，但 Google 登录成功

Question

我尝试在我的 Flutter 应用程序中实现各种 Firebase Auth 方法，当我尝试实现 Firebase Phone Auth (firebase_auth) 时，它显示此错误:

This app is not authorized to use Firebase Authentication. Please verify that the correct package name and SHA-1 are configured in the Firebase Console.

我的包名已经配置好，当我设置我的 Android 应用程序 Firebase 项目时，它连接成功。

关于 SHA-1 key ，我已经将我的 Firebase 控制台配置为包括我的调试 key 和我的发布 key ，我从以下位置获取调试 key :keytool -list -v -alias androiddebugkey -keystore %USERPROFILE%\.android\debug.keystore 我也尝试使用我的发布 key ，并在发布版本中构建我的 apk。

我还重新下载了 google-service.json 并运行 flutter clean 以确保一切都是干净的。

我还确认我在真实的物理设备上运行应用程序，而不是模拟器。但直到此时，我没有运气，仍然陷入(至少 2 天)上述错误。

奇怪的是，当我尝试使用 Google 登录(据我所知)需要正确的 SHA-1 信息登录时，它成功运行了。但是，我在 Firebase Phone Auth 中没有运气。

许多问答仅解决有关在模拟器中或在未配置的 SHA-1 Firebase 控制台中运行 Firebase 电话的问题，或错误的调试/发布 key ，或清理项目。但就我而言，我还没有找到解决问题的方法。

作为引用，这是我使用电话号码登录 dart 代码(我从 firebase_auth/example github repo 获得):

import 'package:flutter/material.dart';
import 'package:firebase_auth/firebase_auth.dart';

final FirebaseAuth _auth = FirebaseAuth.instance;

class SignInPage extends StatefulWidget {
  final String title = 'Registration';
  @override
  State<StatefulWidget> createState() => SignInPageState();
}

class SignInPageState extends State<SignInPage> {
  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: Text(widget.title),
        actions: <Widget>[
          Builder(builder: (BuildContext context) {
            return FlatButton(
              child: const Text('Sign out'),
              textColor: Theme.of(context).buttonColor,
              onPressed: () async {
                final FirebaseUser user = await _auth.currentUser();
                if (user == null) {
                  Scaffold.of(context).showSnackBar(const SnackBar(
                    content: Text('No one has signed in.'),
                  ));
                  return;
                }
                _signOut();
                final String uid = user.uid;
                Scaffold.of(context).showSnackBar(SnackBar(
                  content: Text(uid + ' has successfully signed out.'),
                ));
              },
            );
          })
        ],
      ),
      body: Builder(builder: (BuildContext context) {
        return ListView(
          scrollDirection: Axis.vertical,
          children: <Widget>[
            _PhoneSignInSection(Scaffold.of(context))
          ],
        );
      }),
    );
  }

  // Example code for sign out.
  void _signOut() async {
    await _auth.signOut();
  }
}

class _PhoneSignInSection extends StatefulWidget {
  _PhoneSignInSection(this._scaffold);

  final ScaffoldState _scaffold;
  @override
  State<StatefulWidget> createState() => _PhoneSignInSectionState();
}

class _PhoneSignInSectionState extends State<_PhoneSignInSection> {
  final TextEditingController _phoneNumberController = TextEditingController();
  final TextEditingController _smsController = TextEditingController();

  String _message = '';
  String _verificationId;

  @override
  Widget build(BuildContext context) {
    return Column(
      crossAxisAlignment: CrossAxisAlignment.start,
      children: <Widget>[
        Container(
          child: const Text('Test sign in with phone number'),
          padding: const EdgeInsets.all(16),
          alignment: Alignment.center,
        ),
        TextFormField(
          controller: _phoneNumberController,
          decoration: const InputDecoration(
              labelText: 'Phone number (+x xxx-xxx-xxxx)'),
          validator: (String value) {
            if (value.isEmpty) {
              return 'Phone number (+x xxx-xxx-xxxx)';
            }
            return null;
          },
        ),
        Container(
          padding: const EdgeInsets.symmetric(vertical: 16.0),
          alignment: Alignment.center,
          child: RaisedButton(
            onPressed: () async {
              _verifyPhoneNumber();
            },
            child: const Text('Verify phone number'),
          ),
        ),
        TextField(
          controller: _smsController,
          decoration: const InputDecoration(labelText: 'Verification code'),
        ),
        Container(
          padding: const EdgeInsets.symmetric(vertical: 16.0),
          alignment: Alignment.center,
          child: RaisedButton(
            onPressed: () async {
              _signInWithPhoneNumber();
            },
            child: const Text('Sign in with phone number'),
          ),
        ),
        Container(
          alignment: Alignment.center,
          padding: const EdgeInsets.symmetric(horizontal: 16),
          child: Text(
            _message,
            style: TextStyle(color: Colors.red),
          ),
        )
      ],
    );
  }

  // Example code of how to verify phone number
  void _verifyPhoneNumber() async {
    setState(() {
      _message = '';
    });
    final PhoneVerificationCompleted verificationCompleted =
        (AuthCredential phoneAuthCredential) {
      _auth.signInWithCredential(phoneAuthCredential);
      setState(() {
        _message = 'Received phone auth credential: $phoneAuthCredential';
      });
    };

    final PhoneVerificationFailed verificationFailed =
        (AuthException authException) {
      setState(() {
        _message =
        'Phone number verification failed. Code: ${authException.code}. Message: ${authException.message}';
      });
    };

    final PhoneCodeSent codeSent =
        (String verificationId, [int forceResendingToken]) async {
      widget._scaffold.showSnackBar(const SnackBar(
        content: Text('Please check your phone for the verification code.'),
      ));
      _verificationId = verificationId;
    };

    final PhoneCodeAutoRetrievalTimeout codeAutoRetrievalTimeout =
        (String verificationId) {
      _verificationId = verificationId;
    };

    await _auth.verifyPhoneNumber(
        phoneNumber: _phoneNumberController.text,
        timeout: const Duration(seconds: 60),
        verificationCompleted: verificationCompleted,
        verificationFailed: verificationFailed,
        codeSent: codeSent,
        codeAutoRetrievalTimeout: codeAutoRetrievalTimeout);
  }

  // Example code of how to sign in with phone.
  void _signInWithPhoneNumber() async {
    final AuthCredential credential = PhoneAuthProvider.getCredential(
      verificationId: _verificationId,
      smsCode: _smsController.text,
    );
    final FirebaseUser user =
        (await _auth.signInWithCredential(credential)).user;
    final FirebaseUser currentUser = await _auth.currentUser();
    assert(user.uid == currentUser.uid);
    setState(() {
      if (user != null) {
        _message = 'Successfully signed in, uid: ' + user.uid;
      } else {
        _message = 'Sign in failed';
      }
    });
  }
}

感谢您在之前和之后的回复。

Answer 1

更新:在尝试了将近 2 天的一切之后，我意识到我用来测试 Firebase Phone 的设备已 Root，并安装了自定义 ROM。

当我在未安装的原始 ROM 中尝试使用 firebase phone auth 时，firebase phone auth 工作得很好。

看起来 firebase 手机身份验证不适用于已安装 root 和/或自定义 rom 的设备。

这个问题已经回答了，谢谢大家:)