Java 使用 List 重写构造函数 - "same erasure"错误

Question

您好，我想重写自定义类 MyList 中的构造函数。

下面的代码可以编译，我收到“相同删除”错误。对于编译器List<CustomClass1>与 List<CustomClass2> 类型相同

有人可以建议我如何解决这个问题吗？我尝试使用 List<Object>并使用 instanceof但我无法解决这个问题，但没有成功

private static class MyList {

    private int type;

    public MyList (List<CustomClass1> custom1) {
                 type = 1;
    }

    public MyList (List<CustomClass2> custom2) {
                 type = 2;

    }
}

Answer 1

因为所谓的类型删除 the generic type information is lost during compilation 。当类型信息被删除时，两者都会编译为public MyList(List l)。这就是 Java 的工作原理。泛型仅在编译时可用。

When a generic type is instantiated, the compiler translates those types by a technique called type erasure — a process where the compiler removes all information related to type parameters and type arguments within a class or method. Type erasure enables Java applications that use generics to maintain binary compatibility with Java libraries and applications that were created before generics.