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java - 从同一行读取多个输入。

转载 作者:行者123 更新时间:2023-11-30 04:54:17 24 4
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我正在用java开发一个简单的tcp聊天服务器。用户可以输入“push:”、“get”、“adios”、“help”等命令。 。 。我通过设置 String Line = input.readLine() (如下所示)来检查这些用户命令。问题是当我输入“push:”时,我必须转到新行以获取新输入并将其分配给新字符串。我希望能够在用户键入命令后在同一行获取输入。

例如:如果 USER 1 输入“push:”+“Hello, how are you Today?”我想存储“你好,你今天好吗?”到一个数组,这样我就可以稍后打印它的内容。但现在我必须输入“push:”转到新行并输入“Hello, how are you Today?”将其存储到数组中。这太尴尬了。有什么方法可以将输入存储到同一行上的两个不同字符串吗?

这是我的服务器代码,检查运行方法

// Chat Server runs at port no. 9020
import java.io.*;
import java.util.*;
import java.net.*;
import static java.lang.System.out;

public class TCPServer
{
Vector<String> users = new Vector<String>();
Vector<HandleClient> clients = new Vector<HandleClient>();
Vector<String> Chat = new Vector<String>();

int PORT = 9020;
int NumClients = 10;

public void process() throws Exception
{
ServerSocket server = new ServerSocket(PORT,NumClients);
out.println("Server Connected...");
while(true)
{
Socket client = server.accept();
HandleClient c = new HandleClient(client);
clients.add(c);
} // end of while
}

public static void main(String ... args) throws Exception
{
new TCPServer().process();
} // end of main

public void boradcast(String user, String message)
{
System.out.println(user + ": " + message);
// send message to all connected users
for (HandleClient c : clients)
if (!c.getUserName().equals(user))
{
c.sendMessage(user,message);
}
}

class HandleClient extends Thread
{
String name = "";
BufferedReader input;
PrintWriter output;

public HandleClient(Socket client) throws Exception
{
// get input and output streams
input = new BufferedReader(new InputStreamReader(client.getInputStream())) ;
output = new PrintWriter (client.getOutputStream(),true);
output.println("Welcome to Alan's Chat Server!\n");
// read name
output.println("Please Enter a User Name: ");
name = input.readLine();
users.add(name); // add to vector
output.println("\nWelcome "+name+" we hope you enjoy your chat today");
start();
}

public void sendMessage(String uname,String msg)
{
output.println( uname + ": " + msg);
}

public String getUserName()
{
return name;
}

public void run()
{
String line;
try
{
while(true)
{
line = input.readLine();
line.toLowerCase();//check this
if("adios".equals(line))
{
output.println("\nClosing Connection . . . Goodbye");
clients.remove(this);
users.remove(name);
break;
}
else if(name.equals(line))
{
output.println("OK");
}
else if("help".equals(line))
{
output.println("\nServer Commands:" + "\n\"audios:\" close the client connection\n"+
"\"Name:\" display \"OK\"\n");//Check this
}
else if("push: ".equals(line))
{
String NewLine = input.readLine();
Chat.add(NewLine);
output.println("OK");
}
else if("get".equals(line))
{
output.println(Chat.toString());

}
else
{
boradcast(name,line); // method of outer class - send messages to all
}
}// end of while
} // try
catch(Exception e)
{
System.out.println(e.getMessage());
}
} // end of run()
} // end of inner class
} // end of Server

最佳答案

可以使用String.split("")或使用StringTokenizer

String line = input.read();
String [] d = s.split(":",2);

通过数组索引访问值;

编辑:

为了清楚起见,我将 2 作为 split 方法中的第二个参数传递,因为它将数组的拆分限制为只有两个索引,因此您没有 3 个数组来实现这样的操作:

String.split("PUSH: 我饿了:P"); 因为它会输出 [PUSH;我饿了; ]

关于java - 从同一行读取多个输入。,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9069792/

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