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c++ 类分配的动态数组失败(内存泄漏)

转载 作者:行者123 更新时间:2023-11-30 04:48:24 27 4
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edit1:添加一个正在运行的微型版本。我写了一个包含一些类的 cpp 文件。当我在单个文件中测试它时,一切正常,但是当我将它与其他 c 文件链接时,我存储在类数组中的数据发生了变化。我知道我的内存分配肯定有问题,所以我使用 new 将其更改为动态内存分配但不知道在哪里或如何修复

work in single .cpp file
in a file called test.app
class Board
{
public:
int **grid;
bool done;
int result;

public:
Board()
{
grid = new int*[3];
for(int i = 0; i < 3; ++i){
grid[i] = new int[3];
}
for(int i=0;i<3;i++)
{
for(int j=0;j<3;j++)
{
grid[i][j]=0;
}
}
done=false;
result=0;
}
}

class Node
{

public:
Board **arr;
//double heuristic;
bool done;
int result;
int prevx, prevy;
int next_turn;

public:

Node()

{
arr = new Board*[3];
for(int i=0;i<3;i++)
{
arr[i] = new Board[3];
}
for(int i=0;i<3;i++)
{
for(int j=0;j<3;j++)
{
arr[i][j] = new Board();
}
}
done = false;
//heuristic=0;
result = 0;
prevx = -1;
prevy = -1;
next_turn=1;
}
}

以及出错的代码:

Treenode *head; //treat as global variable

void agent_start( int this_player )
{
//nothing to do
//cout << "here all good" << endl;
head = new Treenode();
//cout << head << endl;
m = 0;
return;

}

int agent_second_move( int board_num, int prev_move )
{
for(int i=0;i<9;i++)
{
for(int j=0;j<9;j++)
{

if(head->arr[res_boardx][res_boardy].grid[cordx][cordy] == 1)
{
cout << "here cant print" << endl;
head->move2(i,j,-1);
cout << "here cant print" << endl;
}
else if(head->arr[res_boardx][res_boardy].grid[cordx][cordy] == -1)
{
cout << "here cant print" << endl;
head->move2(i,j,1);
}
}
}
in test.h
extern int port;
extern char *host;

#ifdef __cplusplus
extern "C" {
#endif
extern char *host;
#ifdef __cplusplus
}
#endif
#ifdef __cplusplus
extern "C" {
#endif
// parse command-line arguments
void agent_parse_args( int argc, char *argv[] );

// called at the beginning of a series of games
void agent_init();

// called at the beginning of each game
void agent_start( int this_player );

int agent_second_move(int board_num, int prev_move );

int agent_third_move(int board_num,int first_move,int prev_move);

int agent_next_move( int prev_move );

void agent_last_move( int prev_move );

// called at the end of each game
void agent_gameover( int result, int cause );

// called at the end of the series of games
void agent_cleanup();
#ifdef __cplusplus
}
#endif
in main.cpp
int main(int argc, char *argv[]){
agent_start(1);
int b = agent_second_move(1,1);
}

输出是:

[1]    26904 illegal hardware instruction

segmentation fault 

在我宣布之前

class Node
{

public:
Board arr[3][3]; ///

在 Node 类中。

导致树节点数据发生变化之前的工作版本

class Board
{
public:
int grid[3][3];
bool done;
int result;

public:
Board()
{
for(int i=0;i<3;i++)
{
for(int j=0;j<3;j++)
{
grid[i][j]=0;
}
}
done=false;
result=0;
}
}
class Node
{

public:
Board arr[3][3];
//double heuristic;
bool done;
int grid[3][3];
int result;
int prevx, prevy;
int next_turn;

public:

Node()
{
for(int i=0;i<3;i++)
{
for(int j=0;j<3;j++)
{
arr[i][j] = Board();
grid[i][j]=0;
}
}
done = false;
//heuristic=0;
result = 0;
prevx = -1;
prevy = -1;
next_turn=1;
}
}

Treenode *head;
head = new Treenode();

void print_map(){
for(int i=0;i<9;i++)
{
for(int j=0;j<9;j++)
{
int res_boardx, res_boardy, cordx, cordy;
res_boardx = (i-1)/3;
res_boardy = (i-1)%3;
cordx = (j-1)/3;
cordy = (j-1)%3;
cout << head->arr[res_boardx][res_boardy].grid[cordx][cordy];
}
cout << endl;
}
}

当我在此之外调用打印功能时,打印出的二维数组如下错误的文件,因为它应该是 1 或 0 或 -1。

433000000
107312758200000000
000000000
000000000
000000000
000000000
00000-1000
000000000
000000000

最佳答案

您没有遵循规则 5。您在构造函数中分配了一些内存,因此您需要一个非默认析构函数来正确释放所有内容,只要显式移动/复制构造函数和赋值运算符即可。

如果可能,您应该坚持使用像 std::vector 这样的标准容器,它会为您处理所有极端情况。

关于c++ 类分配的动态数组失败(内存泄漏),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55810953/

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