android - Android中的随机图像？

Question

我正在尝试使用随机图像制作 View 。我有代码并且没有错误，但是当我单击按钮转到随机图像时，它只是保持不变。

我的来源是:

private static final Random rgenerator = new Random();

private static final Integer[] mImageIds = 
    { R.drawable.img2, R.drawable.img1, R.drawable.img3, };

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Integer q = mImageIds[rgenerator.nextInt(mImageIds.length)];
    ImageView iv = (ImageView) findViewById(R.id.imageviewyeah);
    iv.setTag(q);

    View nextButton = findViewById(R.id.next_image_button);
    nextButton.setOnClickListener(this);
}

public void onClick(View v)
{
    switch (v.getId())
    {
        case R.id.next_image_button:
            Intent i = new Intent(this, RandomImage.class);
            startActivity(i);
            break;
    }
}

Answer 1

只需保留对您的 ImageView 的引用，并使用随机资源之一调用 setImageResource(int id)。您无需启动新的 Activity 即可检索随机资源 ID...

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Integer q = mImageIds[rgenerator.nextInt(mImageIds.length)];
    final ImageView iv = (ImageView) findViewById(R.id.imageviewyeah);

    View nextButton = findViewById(R.id.next_image_button);
    nextButton.setOnClickListener(new OnClickListener() {
         public void onClick(View V) {
              int resource = mImageIds[rgenerator.nextInt(mImageIds.length)];
              iv.setImageResource(resource);
         }
    });
}