java - 友好的 URL 映射问题 - Java Spring

Question

我正在努力解决 web.xml 上的错误，其中所有页面都显示为 404，可能有一个根路径，但我无法确定它的设置位置等..

这是我当前的 web.xml



<pre><code><?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>Spring3MVC</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/*</url-pattern>

</servlet-mapping>
</web-app>
</code></pre>



我的监听器 Controller 是这样的



<pre><code>/*
* User
*/
@RequestMapping(value={"/user/{id}"}, method=RequestMethod.GET)
public ModelAndView profileDisplay(
HttpServletRequest request,
HttpServletResponse response,
@RequestParam(value="id", required=false) String id
) throws UnknownHostException, MongoException {
ServiceSerlvet.appendSesssion(request);
//get search ALL users
BasicDBObject searchQuery = new BasicDBObject();
searchQuery.put("_id", new ObjectId(id));
List<DBObject> searchResponse = PersonController.searchUsers(searchQuery);

//System.out.println("response from search user method: "+searchResponse);

return new ModelAndView("user", "people", searchResponse);
}
</code></pre>



这是当前出现的错误。为什么它没有映射，我该如何解决这个问题？

INFO: Server startup in 5904 ms
01-Nov-2012 19:40:21 org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/springApp21] in DispatcherServlet with name 'spring'
01-Nov-2012 19:40:22 org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/user', method 'GET', parameters map['id' -> array<String>['4fa6eddc0234964172522248']]
01-Nov-2012 19:40:24 org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/user', method 'GET', parameters map['id' -> array<String>['4fa6eddc0234964172522248']]

Answer 1

我事先就想到了你的一个问题。我现在可以访问我的 Spring 应用程序之一。这是一个更好的配置。

请注意 web.xml 的更改，我很抱歉，但映射到/* 会导致调度程序解决您的所有请求。从某种意义上说，您创建了一个循环，您的初始映射将由调度程序转发到 Controller ，然后 Controller 将使用 View 解析器来映射您的请求应转发到的位置。映射到/* 导致 View 解析器映射由调度程序处理。

更改为/会导致所有未映射的 url 由调度程序处理，因此您的初始映射由调度程序处理，调度程序将其发送到 Controller ，并且 viewresolver 创建的映射将被映射到 .jsp，从而导致它不会被调度员接走。抱歉。

Web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>Spring3MVC</display-name>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>
                  org.springframework.web.servlet.DispatcherServlet
              </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/</url-pattern>

  </servlet-mapping>
</web-app>

spring-config.xml(您必须更改组件扫描)

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">

    <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

    <!-- Enables the Spring MVC @Controller programming model -->   
    <annotation-driven/>

        <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
    <resources location="/resources/" mapping="/resources/**"/> 

    <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <beans:property name="prefix" value="/WEB-INF/views/"/>
        <beans:property name="suffix" value=".jsp"/>
    </beans:bean>

    <context:component-scan base-package="package.with.controllers" />

</beans:beans>

Controller

@RequestMapping(value={"/user/{id}"}, method=RequestMethod.GET)
public ModelAndView profileDisplay(
        HttpServletRequest request, 
        HttpServletResponse response,
        @RequestParam(value="id", required=false) String id
) throws UnknownHostException, MongoException {
    ServiceSerlvet.appendSesssion(request);
    //get search ALL users
    BasicDBObject searchQuery = new BasicDBObject();
        searchQuery.put("_id", new ObjectId(id));
    List<DBObject> searchResponse = PersonController.searchUsers(searchQuery);      

    //System.out.println("response from search user method: "+searchResponse);

        //This should display "WEB-INF/views/user.jsp" you may need to adjust.
        return new ModelAndView("user", "people", searchResponse);
}