c++ - 不按回车进入下一条指令

Question

我的问题是在不按回车键的情况下尝试转到下一条指令。这是我的代码

cout<<"Enter Date Of Birth: ";
cin>>day;
cout<<"/";
cin>>month;
cout<<"/";
cin>>year;

通过只为一天提供 2 位数字，我希望在不按 enter 键的情况下打印下一条指令，然后转到其余的月份和年份。由于年份是最后一年，我可以在那之后按回车键。

Answer 1

你可以这样写一个函数:

#include <iostream>
#include <sstream>
#include <conio.h>
#include <vector>
#include <math.h>

int getInput(int count)
{
    int i = 0;
    std::stringstream ss;

    while (count)
    {
        char c = _getch();
        std::cout << c;
        ss << c;
        count--;
    }

    ss >> i;
    return i;
}

int getInput_(int count)
{
    int num = 0;

    std::vector <int> v;

    while (count)
    {
        char c = _getch();
        std::cout << c;
        v.push_back(atoi(&c));
        count--;
    }

    for (size_t i = 0; i < v.size(); i++)
    {
        num += (int)(v[i] * (pow((float)10, (float)(v.size()-1)-i)));
    }

    return num;
}

int main()
{
    int day = 0, month = 0, year = 0;

    day = getInput_(2);

    std::cout << "/";

    month = getInput_(2);

    std::cout << "/";

    year = getInput_(4);

    std::cout << std::endl << day << "/" << month << "/" << year;
}