javascript读取新的rss条目并创建通知

Question

I want to create a javascript which checks if a new rss feed has been updated and display a notification using phonegaps notification methods. http://docs.phonegap.com/phonegap_notification_notification.md.html#Notification

     var oldEntry="";
 document.addEventListener("deviceready", onDeviceReady, false);

    // PhoneGap is ready
    //
    function onDeviceReady() {
        // Empty
    }

    // Show a custom alert
    //

    function sendRequest(){

      getRss("http://rss.cnn.com/rss/cnn_latest.rss.xml");      
      setTimeout('showAlert(newEntry.title)',4000);

    }


    function showAlert(data) {
     var st = randomString();
     if(oldEntry==""){
        oldEntry = data;
        navigator.notification.alert(
                data,  // message
                'New Rss Entry',            // title
                'New Rss Entry'              


        );        
     }

     else {
       if(oldEntry!=data){
        navigator.notification.alert(
                data,  // message
                'New Rss Entry',            // title
                'New Rss Entry'              


        );
        oldEntry = data;

       }
       }

       setTimeout('sendRequest()',8000);
    }

    function randomString() {
        var chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz";
        var string_length = 8;
        var randomstring = '';
        for (var i=0; i<string_length; i++) {
            var rnum = Math.floor(Math.random() * chars.length);
            randomstring += chars.substring(rnum,rnum+1);
        }
        return randomstring;
    }

   sendRequest();

现在新的和旧的 Rss 标题都会作为通知弹出，是否可以限制该功能只显示最新的 Rss 标题？

即使我在 8000 毫秒后关闭了这两个通知，它们都再次出现，但我想检查是否有任何新通知并只显示它们，而不是用户已关闭的通知。

这是为了获取新条目。

    var newEntry="";
        function getRss(url){
        if(url == null) return false;

                    // Create Google Feed API address
                    var api = "http://ajax.googleapis.com/ajax/services/feed/load?v=1.0&callback=?&q="
    + encodeURIComponent(url);

                    api += "&output=json_xml"

                    // Send request
                    $.getJSON(api, function(data){

                        // Check for error
                        if (data.responseStatus == 200) {

                            // Process the feeds
                            _process(data.responseData);

                        } 
                                  else {

                        };
                    });             

        }

        var _process = function(data) {

                // Get JSON feed data
                var feeds = data.feed;
                if (!feeds) {
                    return false;
                }

// Get XML data for media (parseXML not used as requires 1.5+)
                var xml = getXMLDocument(data.xmlString);
                var xmlEntries = xml.getElementsByTagName('item');
                var entry = feeds.entries[0];
                newEntry = entry;

            };

Answer 1

可能会有很多问题。我想也许你遇到了缓存错误。所以尝试添加这个 -

api += "&tempVar="+ Math.random()

在你的代码之后 -

api += "&output=json_xml"