Android - 使用 while 循环停止线程

Question

奇怪的问题似乎在这里被提到过几次。我有一个线程，也使用了 AsyncTask，我正试图根据用户的请求让它停止运行。所以，很自然地，我在 while 循环中使用了一个 bool 值。该线程始终将该 bool 值视为 true，即使它在其他地方打印 false 也是如此。

代码如下，如有任何帮助，我们将不胜感激!

/**
 * Opens new socket and listens on the specified port until a user stops the thread, the logview is updated with messages
 */
public void run() {
    byte[] receiveData = new byte[1024];
    byte[] sendData = new byte[1024];
    Log.e("Text2Server", "Starting Server");
    this.running = true;
    while(this.running) {
        Log.i("Text2Server", "Server should be running: " +  running);
        try {
            serverSocket = new DatagramSocket(port);
        } catch (SocketException e1) {
            e1.printStackTrace();
        }
        try {   
            DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
            serverSocket.receive(receivePacket);
            final String fromIP = new String(receivePacket.getAddress().toString());
            final int fromPort = receivePacket.getPort();
            final String received = new String(receivePacket.getData());
            Date now = new Date();
            final String logput = DateFormat.getDateTimeInstance().format(now) + " - Message from: " + fromIP + " through Port: " + fromPort + " with Message: " + received;
            Log.i("Text2Server", logput);
            //All UI Operations are done in this thread
            uiHandler.post(new Runnable(){
                @Override
                public void run() {
                    logTextView.append(logput);
                }                   
            });
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
    serverSocket.close();
}

public void stopThread() {
    this.running = false;
    Log.i("Text2Server", "Stopping Server, value is now: " + running);
}

调用 stopThread() 使其为 false，但线程仍然进入 while 并打印出 true。有什么想法吗？

谢谢!

Answer 1

可能的原因:

1) 您已经生成了多个线程并且只关闭了其中一个。

2) 在线程开始运行之前调用stopThread。

3) 该线程已在 UI 线程上排队等待许多 logTextView.append(logput) 调用，因此看起来之后仍在运行。