gpt4 book ai didi

Java多线程时间切换

转载 作者:行者123 更新时间:2023-11-30 04:19:31 26 4
gpt4 key购买 nike

我对 Java 中多线程如何在底层工作的了解很少。据我所知,当有两个线程运行时,Java 会为每个线程分配“时间 block ”来执行。

例如:

public void test()
{
Thread testThread = new Thread(new TestThread());
testThread.start();

for (int i = 0; i < Integer.MAX_VALUE; ++i)
System.out.print("a");
}

private class TestThread extends Thread
{
public void run()
{
for (int i = 0; i < Integer.MAX_VALUE; ++i)
System.out.print("b");
}
}

会打印出类似的内容:
啊啊啊aaaaaabbbbbbbbbbbbbaaaaaaaaaaabbbbbbbbbbbbbaaaaaa...
而不是:
babababababababababababababababab......


我的问题是:是否可以减少“时间 block ”,以便我们得到更接近的结果:
aabbaabbaabbaaabbaabbbaabbaabbbaabbaaa...


为什么?我正在尝试编写一个苹果推送通知服务器(只是为了好玩)。当您向苹果推送通知服务写入请求时,可能会发生一两件事:
1. 如果请求有效,则不会返回任何内容。
2. 如果请求无效,将返回错误码并关闭连接,无效请求之后、连接关闭之前发送的所有请求都将被丢弃。

因为读取套接字会阻塞,直到有数据可供读取(如果我不写入任何无效请求,这种情况可能永远不会发生),所以我不能在每次写入后简单地读取以查看是否存在错误,而不设置 200-500 毫秒的超时。如果我们有 100 万个写入请求(很可能),则超时时间将增加 55 - 138 小时,并且由于超时时间短,我们可能会错过返回的错误,从而导致请求永远不会被发送。

因此,我有两个线程,如上面的示例,一个正在写入服务器,另一个正在读取,等待查看是否返回错误。问题是这样的:如果请求 #4 是错误的,但我们在读取错误和连接关闭之前写入了 #5-#10,则请求 #5-10 会被 Apple 服务丢弃。因此,一旦我们知道#4是坏的并且我们知道我们写的最后一个请求是#10,我们需要重新排队#5-10以再次发送。

我现在遇到的问题是由于“时间卡盘”很大,我能够在读取线程读取 #5 存在错误之前写入请求 #1-#400,因此 #6-#400 被重新排队并发送再次。然后读取线程读取 #21 存在错误,因此 #22-#400 重新排队并再次发送...等等。理想情况下,读取线程能够在每写入 5-10 个请求时从套接字读取数据。

来源:

private Object readWriteLock = new Object();
private volatile int lastWrittenIndex;
private volatile boolean doneWriting;
private List<PushNotificationRequest> pushNotificationRequestsResnedList = new ArrayList<PushNotificationRequest>();

public boolean write()
{
// get the requests read list
List<PushNotificationRequest> requests = getPushNotificationRequests(false);

// as long as there are more notifications to write...
while (requests.size() > 0)
{
lastWrittenIndex = -1;
doneWriting = false;

// create and start the read thread
Thread readThread = new Thread(new ReadThread(), "APNS Reader");
readThread.start();

for (int i = 0; i < requests.size(); ++i)
{
PushNotificationRequest request = requests.get(i);

// write
boolean success = false;

// attempt to send the notification a number of times
for (int j = 0; j < MAX_NUM_PN_WRITE_ATTEMPTS; ++j)
{
synchronized (readWriteLock)
{
try
{
// get the socket connection
SSLSocket socket = getAppleServiceSSLSockett();
OutputStream socketOutputStream = socket.getOutputStream();

socketOutputStream.write(request.binary);
socketOutputStream.flush();

success = true;
lastWrittenIndex = i;

break;
}
catch (IOException e)
{
e.printStackTrace();
}
catch (AppleServiceConnectionException e)
{
e.printStackTrace();
}
}
}

if (!success)
System.err.println("APNS Unable to send push notification:\n" + request);
}

// wait for some time so we can make sure the read thread can read everything
try
{
Thread.sleep(Config.APNS_READ_TIME_AFTER_DONE_WRITING_MILLISECONDS);
}
catch (InterruptedException e)
{
e.printStackTrace();
}

// let the read thread know we are done writing and close the connection so it unblocks
doneWriting = true;
closeAppleServiceSSLSockett();

// wait for the read thread to return
try
{
readThread.join();
}
catch (InterruptedException e)
{
e.printStackTrace();
}


// clear the reading list
requests.clear();

// add the requests from the re-send to the list
if (pushNotificationRequestsResnedList.size() > 0)
{
requests.addAll(pushNotificationRequestsResnedList);

// clear the re-send list
pushNotificationRequestsResnedList.clear();
}
}
}

private class ReadThread extends Thread
{
public void run()
{
byte[] readBuffer = new byte[1024];
int numBytesRead;
int totalNumBytesRead;

while (!doneWriting)
{
try
{
// get the socket connection
SSLSocket socket = getAppleServiceSSLSockett();
socket.setSoTimeout(Config.APNS_READ_TIMEOUT_MILLISECONDS);

InputStream socketInputStream = socket.getInputStream();

// read (blocking)
totalNumBytesRead = 0;
while ((numBytesRead = socketInputStream.read(readBuffer)) != -1)
totalNumBytesRead += numBytesRead;

// check for an error
if (totalNumBytesRead > 0)
{
synchronized (readWriteLock)
{
try
{
PushNotificationResponse response = new PushNotificationResponse(readBuffer, 0);
System.err.println("APNS Read got response with id: " + response.identifier);

// find the request with the given identifier
int i;
for (i = lastWrittenIndex; i > -1; --i)
{
if (pushNotificationRequestsReadingList.get(i).identifier == response.identifier)
break;
}


if (i == -1)
{
// something went wrong, we didn't find the identifier
System.err.println("APNS Read unable to find request with id: " + response.identifier);
}
else
{
System.err.println("APNS Read " + response.getErrorMessage(pushNotificationRequestsReadingList.get(i)));

// add the requests between the bad request and the last written (included)
for (++i; i <= lastWrittenIndex; ++i)
pushNotificationRequestsResnedList.add(pushNotificationRequestsReadingList.get(i));
}
}
catch (InvalidPushNotificationResponseException g)
{
g.printStackTrace();
}
}

// the socket will be closed, reopen it
try
{
reopenAppleServiceSSLSockett();
}
catch (AppleServiceConnectionException e)
{
e.printStackTrace();
}
}
}
catch (SocketException e)
{
// ignore a close, it is expected
if (!e.getMessage().equals("Socket closed"))
e.printStackTrace();
}
catch (IOException e)
{
e.printStackTrace();
}
catch (AppleServiceConnectionException e)
{
e.printStackTrace();
}
}
}
}

最佳答案

它不是java,而是操作系统实际上为线程调度时间 block 。在生产者/消费者场景中,您希望在生产者方面提供公平性,以便一个生产者在所有其他生产者给出自己的输出后给出一个输出。为此,您可以使用一个线程来轮询几个懒惰的生产者。即:

N 个生产者公开 getNextThing() 和 1 个消费者对生产者进行循环并将结果通过管道传输到您使用的列表

关于Java多线程时间切换,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17436245/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com