c++ - 没有匹配函数调用 'Book::Book()'

Question

我正在为 MIT OCW 类(class)做一些事情，它要求编写一个“图书馆”类(class)。现在我有这个:

#include <iostream>

using namespace std;

class Book{
    string title;
    bool rented;
public:
    Book(string bookTitle){
        title = bookTitle;
    }
    void borrowed(){
        rented = true;
    }
    void returned(){
        rented = false;
    }
    bool isBorrowed(){
        return rented;
    }
    string getTitle(){
        return title;
    }
};

class Library{
    string Lname;
    Book bookList[100000000];
    int numOfBooks = 0;
public:
    Library(string name){
        Lname = name;
    }
    void addBook(string bookName){
        bookList[numOfBooks] = Book(bookName);
        numOfBooks += 1;
    }
    void returnInfo(){
    cout << "Library hours:" << "\n" << "Libraries are open daily from 9am to 5pm." << "\n" << "Library addresses:" << "\n" << "10 Main St." << "\n" << "228 Liberty St.";
    }

};
int main()
{
    Library l = Library("Hi");
    return 0;
}

当我编译时，它给出了第 35 行没有匹配函数调用 'Book::Book()' 的错误。

Answer 1

编译器提示你没有为 Book 定义默认构造函数，你可以试试这个:

 explicit Book(const string& bookTitle = std::string("")) 
 : title(bookTitle) 
 {
 }

在堆栈上定义 100000000 导致溢出，

Book bookList[100000000];

尝试改用 vector

std::vector<Book> bookList;

在 addBook 中，您可以简单地使用 std::vector::push_back添加一本新书。要获得总书数，请使用 std::vector::size()

void addBook(const string& bookName){
    bookList.push_back(Book(bookName));
}

建议:

1. To pass parameter to function like std::string, pass by const
2. reference is a better way. use member initialization list if possible

 Library(const string& name) : Lname(name) {  }
 void addBook(const string& bookName){ }