gpt4 book ai didi

android - 如何在谷歌地图中获取解析 url 以获取有关 android 中位置和邻域的详细信息

转载 作者:行者123 更新时间:2023-11-30 04:16:06 26 4
gpt4 key购买 nike

这是我的代码

public static JSONObject getLocationInfo(String address) {
StringBuilder stringBuilder = new StringBuilder();
try {

// address = address.replaceAll(" ","%20");

HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
stringBuilder = new StringBuilder();


response = client.execute(httppost);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}

JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

return jsonObject;
}

我在响应中收到一个 json 异常。请告诉我一个有效的网址。我还为 gps 做了 mapview(api key 和 android list 许可)。

日志:

04-03 16:35:20.548: E/CheckinTask(202): java.net.UnknownHostException: android.clients.google.com
04-03 16:35:20.548: E/CheckinTask(202): at java.net.InetAddress.lookupHostByName(InetAddress.java:506)
04-03 16:35:20.548: E/CheckinTask(202): at java.net.InetAddress.getAllByNameImpl(InetAddress.java:294)
04-03 16:35:20.548: E/CheckinTask(202): at java.net.InetAddress.getAllByName(InetAddress.java:256)
04-03 16:35:20.548: E/CheckinTask(202): at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:136)
04-03 16:35:20.548: E/CheckinTask(202): at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164)
04-03 16:35:20.548: E/CheckinTask(202): at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119)
04-03 16:35:20.548: E/CheckinTask(202): at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:359)
04-03 16:35:20.548: E/CheckinTask(202): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555)
04-03 16:35:20.548: E/CheckinTask(202): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487)
04-03 16:35:20.548: E/CheckinTask(202): at android.net.http.AndroidHttpClient.execute(AndroidHttpClient.java:248)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.common.http.GoogleHttpClient.executeWithoutRewriting(GoogleHttpClient.java:203)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.common.http.GoogleHttpClient.execute(GoogleHttpClient.java:245)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.common.http.GoogleHttpClient.execute(GoogleHttpClient.java:313)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.gsf.checkin.CheckinTask.sendRequest(CheckinTask.java:254)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.gsf.checkin.CheckinTask.doInBackground(CheckinTask.java:150)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.gsf.checkin.CheckinService$1.doInBackground(CheckinService.java:221)
04-03 16:35:20.548: E/CheckinTask(202): at com.google.android.gsf.checkin.CheckinService$1.doInBackground(CheckinService.java:214)
04-03 16:35:20.548: E/CheckinTask(202): at android.os.AsyncTask$2.call(AsyncTask.java:185)
04-03 16:35:20.548: E/CheckinTask(202): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:306)
04-03 16:35:20.548: E/CheckinTask(202): at java.util.concurrent.FutureTask.run(FutureTask.java:138)
04-03 16:35:20.548: E/CheckinTask(202): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1088)
04-03 16:35:20.548: E/CheckinTask(202): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:581)
04-03 16:35:20.548: E/CheckinTask(202): at java.lang.Thread.run(Thread.java:1019)

最佳答案

试试这个:

    private String getJSONFile(String URL) {
HttpGet httpGet = new HttpGet(URL);
HttpClient httpClient = new DefaultHttpClient();
HttpResponse httpResponse;
StringBuilder stringBuilder = new StringBuilder();

try {
httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
InputStream inputStream = httpEntity.getContent();
int c;
while ((c = inputStream.read()) != -1) {
stringBuilder.append((char) c);
}
} catch (Exception e) {
e.printStackTrace();
}

return stringBuilder.toString();
}

关于android - 如何在谷歌地图中获取解析 url 以获取有关 android 中位置和邻域的详细信息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9991616/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com