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c++ - 无法成功创建唯一对象的 std::list

转载 作者:行者123 更新时间:2023-11-30 04:15:09 25 4
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我有一个基于 OpenGL GLUT(是的,我知道,GLUT 很古老)的 C++ 程序,它交替打印出一个蓝色矩形和一个红色正方形,位于 GLUT 窗口中用户单击鼠标的位置。这工作正常。

然而,当我试图修改上述程序以使上述形状在初始动画后保留在 Canvas 上时,我遇到了令人难以置信的麻烦。

我创建了一个 Shape 类,它包含顶点数、颜色、坐标等信息。当程序一次只绘制一个形状时,该类似乎功能齐全。

为了解决一次多个形状的问题,我创建了一个 std::list<Shape>链表。但是,当我通过 std::list<Shape>::iterator 遍历链表时机制,对象似乎在内存中捆绑在一起。也就是说,对于链表中的每个索引,迭代都会产生完全相同的形状对象、坐标和所有内容。

我尝试了以下解决方案:

使链表成为std::list<Shape*>而不是 std::list<Shape> ,

  • 通过Shape* my_shape = new Shape(params)利用堆分配对象,
  • 并结合上述两种方法。

这是我的 void display() GLUT 函数,以及相关的全局变量和类定义/声明:

class Shape
{

public:
Shape();
Shape(int, double[], int[]);
int type; //0 = rectangle, 1 = circle, 2 = triangle
int numVertices; //stores total number of vertices in the 2D object.
double* vertexArray; //a dynamic array that stores each vertex's (x, y)-coordinates in alternating successive indices
int* rgb; //an array that contains the 3 rgb values s.t. rgb = {r, g, b}
double* center; //an array that contains the (x, y)-coordinates of the shape's center on the 2d plane.
int velocity[2]; //a array of size 2 that holds the object's x-velocity in index 0 and the object's y-velocity in index 1

};

//default Shape constructor
Shape::Shape()
{

}

//Shape constructor
Shape::Shape(int shapeType, double vertices[], int color[]) //constructor for creating a stationary 2D shape
{
type = shapeType;

if (shapeType!=1) //as long as shape is NOT a circle, interpret the second constructor parameter as a list of vertices
{
vertexArray = vertices;
}

rgb = color;

if (shapeType==0) //shape is a rectangle
{
numVertices = 4;
}
else if(shapeType==1) //shape is a circle
{
//shape is a circle, therefore the second array param is in fact an array of size 2 containing the (x, y)-coordinates of the circle origin...
center = vertices;
}
else if (shapeType==2) //shape is a triangle
{
numVertices = 3;
}
}


std::list<Shape> shapeList;
void my_display(void)
{
/* clear the buffer */
glClear(GL_COLOR_BUFFER_BIT);


//altFlag is just a value to allow alternating between rectangles/circles being printed

if (altFlag==1)
{
printf("Drawing rectangle at: (%g, %g)\n", my_x, my_y);

/*instantiate a Shape() object representing a blue rectangle*/
int rgbColor[3] = {0, 0, 1};

double vertices[4] = {my_x/window_w, my_y/window_h, my_x/window_w + my_rect_w, my_y/window_h + my_rect_h};

Shape my_rectangle(0, vertices, rgbColor); //uses constructor (shape type, list of vertex coordinates, length of coordinate list, color)

glColor3f((GLfloat)my_rectangle.rgb[0], (GLfloat)my_rectangle.rgb[1], (GLfloat)my_rectangle.rgb[2]) ; /* (Red, Green, Blue); so here we ask for Blue */
glRectf(my_rectangle.vertexArray[0], my_rectangle.vertexArray[1], my_rectangle.vertexArray[2], my_rectangle.vertexArray[3]); //call to function to draw a rectangle
altFlag=0;

shapeList.push_front(my_rectangle);
}
else
{
/*instantiate a Shape() object representing a red circle*/
int circleColor[3] = {1, 0, 0};
double circleCenter[2] = {(my_x), (my_y)}; //{center x coord, center y coord}
//Shape* my_circle = new Shape(1, circleCenter, circleColor);
Shape my_circle(1, circleCenter, circleColor);

glColor3f(my_circle.rgb[0], my_circle.rgb[1], my_circle.rgb[2]);
glCirclef(my_circle.center[0], my_circle.center[1]); //call to function to draw pseudocircle

altFlag=1;

shapeList.push_front(my_circle);
}

//iterate over shapeList, print out values of the rgb array.
for (std::list<Shape>::iterator iter = shapeList.begin(); iter != shapeList.end(); iter++)
{
printf("%d, %d, %d\n", iter->rgb[0], iter->rgb[1], iter->rgb[2]);
}

glutSwapBuffers();

return;

虽然这是作业的一部分,但问题与所使用的语言有关,而不是类(class)重点的图形库。

最佳答案

Shape 的参数化构造函数这样做:

vertexArray = vertices;

在哪里vertices是声明为 double vertices[] 的函数参数.这是 double *vertices 的语法糖,即,您正在复制一个指针(因为数组在传递给函数时会退化为指针)。

vertexArray被定义为类内部的指针。您甚至提到它是一个“动态数组”,但随后您使用在堆栈上分配的数组( display() 中的局部变量)对其进行了初始化。这使得指针悬空。

你必须制作 vertexArray一个数组并复制数据,而不仅仅是指针。像这样:

class Shape
{
// ...
double vertexArray[4];
// ...
};

Shape::Shape(int shapeType, double vertices[], int color[])
{
type = shapeType;

if (shapeType==0) //shape is a rectangle
{
numVertices = 4;
}
else if(shapeType==1) //shape is a circle
{
//shape is a circle, therefore the second array param is in fact an array of size 2 containing the (x, y)-coordinates of the circle origin...
center = vertices;
}
else if (shapeType==2) //shape is a triangle
{
numVertices = 3;
}

if (shapeType!=1) //as long as shape is NOT a circle, interpret the second constructor parameter as a list of vertices
{
std::copy(vertices, vertices + numVertices, vertexArray);
}
}

类推color当然还有。

额外建议

当然,这段代码使用std::vector会好得多或类似的东西而不是普通数组,使用和 enum而不是 int对于 shapeType等。我建议你拿起一个 good C++ book .

关于c++ - 无法成功创建唯一对象的 std::list,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18509995/

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