android - 如何设置报警信息？

Question

In alarm app, user gives input String for alarm message and sets alaram. I am able to set and listen alarm.but how to display message set by user? have set many times to set alarm, how can i display respective message for that specific alarm

Answer 1

您的 BroadcastReceiver 中应该有一个 onReceive(Context context, Intent intent) 函数。它看起来像:

public void onReceive(Context context, Intent intent) {   
    PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
    PowerManager.WakeLock wl = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK, ""); // Second argument is an arbitrary String tag
    wl.acquire();

    // Put YOUR code here (between WaitLocks)
    String userInputtedString = intent.getBundleExtra("UserText")
    Toast.makeText(context, userInputtedString, Toast.LENGTH_LONG).show();

    wl.release();
}

为了获得该 Bundle，您必须在创建警报时额外传递一个 intent

Intent intent = new Intent(context, AlarmNotification.class);
intent.putExtra("UserText", userInputedString);
PendingIntent pendingIntent = PendingIntent.getBroadcast(context, 0, intent, 0);

我刚刚展示了一个 Toast 消息示例，但您也可以将其更改为 Notification 或 AlertDialog。如果这有帮助，请告诉我。