java - 覆盖 JPA MappedSuperClass 通用属性

Question

我有以下场景，我需要子类能够指定 MappedSuperClass 中找到的属性的实际类型。我使用 hibernate 作为提供程序，并且我不介意使用 hibernate 特定注释来解决这个问题。

@MappedSuperclass
abstract class BaseA{
   ....

   @OneToMany(mappedBy = "baseA")
   public Set<? extends BaseB> getBaseB(){
      .....
   }
}

@MappedSuperclass
abstract class BaseB{
   .....

   @ManyToOne(optional = false)
   @JoinColumn(name = "basea_id")
   public BaseA getBaseA(){
      .....
   }
}

@Entity
class BaseAImpl extends BaseA{
    public Set<BaseBImpl> getBaseB(){
      .....
   }
}

@Entity    
class BaseBImpl{

   public BaseAImpl getBaseA(){
      .....
   }
}

Answer 1

@AssociationOverride 在这种情况下将为您提供帮助。请参阅documentation对于它(当然是JPA注解)。您可以将它与 @AttributeOverrides 注释结合使用来覆盖基本类型。示例(取自示例):

@MappedSuperclass
public class Employee {
    ...
    @ManyToOne
    protected Address address;
    ...
}

@Entity 
@AssociationOverride(name="address", 
                         joinColumns=@JoinColumn(name="ADDR_ID"))
    // address field mapping overridden to ADDR_ID foreign key
public class PartTimeEmployee extends Employee {
    ...
}