c++ - 使用 cout 和函数调用结构参数的结构输出

Question

所以，问题是编译时的几个错误。

ReadMovieData(string* title, string* director) cannot convert from movieInfo to string*

DisplayMovieData(string title, string director) cannot convert from movieInfo to string

No operator found which takes a right-hand operand of type 'movieInfo' (or there is no acceptable conversion. 

底部错误在 DisplayMovieData() 中发生两次，因此为了简单起见，我只写了一次。

ReadMovieData 函数应接受结构指针引用变量，DisplayMovieData 函数应接受 MovieInfo 结构变量。

main 函数创建一个包含 2 个 MovieInfo 结构变量的数组，其他函数应该在数组的一个元素上调用。

我完成的代码如下。

#include <stdafx.h>
#include <string>
#include <iomanip>
#include <iostream>
using namespace std;

//prototypes
int ReadMovieData(string* title, string* director);
int DisplayMovieData(string title, string director);

struct movieInfo {
    string title, director;
};

int main(){

    const int SIZE = 2;
    movieInfo movieList[SIZE];
    movieInfo movie;

    //supposed to assign data to movieList[i] at some point
    for (int i = 0; i < SIZE; i++){
        ReadMovieData(movie, movie);
        DisplayMovieData(movie, movie);
    }
    return 0;
}

int ReadMovieData(movieInfo &title, movieInfo &director){

    movieInfo movie;

    //get the movie name
    cout << "What is the movie? ";
    cin.ignore();
    cin >> movie.title;

    //get the movie director
    cout << "What is the director of " << movie.title << "?";
    cin.ignore();
    cin >> movie.director;

    return 0;
}

int DisplayMovieData(movieInfo title, movieInfo director){

    cout << "The movie name is: " << title << endl;
    cout << "The director of " << title << " is: " << director << endl;

    return 0;
}

Answer 1

您的函数原型(prototype)和它们的定义之间存在不匹配，您可以比较两者的参数类型。

请注意，由于您为电影信息定义了一个结构，因此您可以直接将其传递给读取和显示函数(而不是传递单个结构数据成员字符串)。

您可能需要阅读以下可编译代码:

#include <iostream>
#include <string>
using namespace std;

struct MovieInfo {
    string title;
    string director;
};

void ReadMovieData(MovieInfo& movie);
void DisplayMovieData(const MovieInfo& movie);

int main() {
    const int SIZE = 2;
    MovieInfo movieList[SIZE];

    for (int i = 0; i < SIZE; i++) {
        ReadMovieData(movieList[i]);
        DisplayMovieData(movieList[i]);
    }
}

// Since movie is an output parameter in this case, pass by non-const reference.
void ReadMovieData(MovieInfo& movie) {
    //get the movie name
    cout << "What is the movie? ";
    cin >> movie.title;

    //get the movie director
    cout << "What is the director of " << movie.title << "?";
    cin >> movie.director;
}

// Since movie is an input parameter in this case, pass by reference to const.
void DisplayMovieData(const MovieInfo& movie) {
    cout << "The movie name is: " << movie.title << endl;
    cout << "The director of " << movie.title 
         << " is: " << movie.director << endl;
}