java - Spring MVC 转发到新 URL 并保持现有状态

Question

我试图重定向到上一页，但域对象无效。例如，使用地址域对象。

@Autowired 
private Address address;
@RequestMapping(method = RequestMethod.GET)
public String addressPage(
  ModelMap model
) throws StdAddFault {
  model.addAttribute("address", address);
  return TILE_GET_STARTED_ADDRESS;
}
@RequestMapping(value = "/validate", method = RequestMethod.POST)
public String selectAddress(
  @Valid Address address,
  BindingResult result,
  Model model,
  HttpSession session
) throws StdAddFault {
  if(result.hasErrors()) {
    model.addAttribute("address", address);
    return "/address";
  }
  ...
}

问题是在请求之后，而不是/address，而是/address/validate。这似乎有点误导，但如果我使用重定向或转发，我就会丢失我的信息。

有什么方法可以将 url 设置在 Controller /地址之后(仅适用于无效数据)？

更新

我确认以上方法不起作用。这确实有效，但我担心一个请求可能会覆盖另一个请求的地址。这是一个合理的担忧吗？

if(result.hasErrors()) {
  this.address = address;
  return "redirect:/get-started/address";
}

Answer 1

我认为您想要的是存储在 session 中的“地址”模型属性。这将保留每个用户 session 的唯一地址对象

@Controller
@SessionAttributes({"address"})
@RequestMapping("/address")
public class AddressController {

  /**
   * Injected model reference will contain 'address' if it exists in session
   */
  @RequestMapping(method = RequestMethod.GET)
  public String addressPage(Model model) {
    if(!model.containsAttribute("address"))
      model.addAttribute("address", new Address());
    return "address";
  }

  /**
   * This handler maps to form selecting / updating the address object
   * at the end of this method the address object is automatically
   * stored in session
   */
  @RequestMapping(value = "/validate", method = RequestMethod.POST)
  public String selectAddress(@ModelAttribute("address") Address address) {
    // do stuff with the newly updated address..
  }
}

如果在任何其他处理程序中您需要地址对象，您所需要做的就是在参数上注入(inject) @ModelAttribute("address") Address address