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java - 循环程序在完成检查后再次启动

转载 作者:行者123 更新时间:2023-11-30 03:57:24 24 4
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我正在尝试编写一个程序,用户在 a 和 b 上输入一个字符串,程序将检查它是否被接受。现在,如果用户输入“退出”,我设法使程序退出,但我无法弄清楚如何循环程序并使其在完成检查字符串时再次启动,要求用户再次输入。我该怎么做呢?下面是我的代码

import java.util.Scanner; 
public class Automata {
public static void main(String[] args) {
Boolean keeprunning = true;
Scanner inputScanner = new Scanner(System.in);
System.out.println("Please enter your input");
String input = inputScanner.next();
char [] Inputted = input.toCharArray();

if (input.equalsIgnoreCase("Exit")){
keeprunning = false;
System.out.println("Exit now");
}

String stateA = "A";
String stateB = "B";
String stateC = "C";
String stateD = "D";
String stateE = "E";
String stateF = "F";
String currentState = "A";

while(keeprunning){
for (int i = 0; i < Inputted.length; i++){
if (Inputted[i]=='a' && currentState.equals(stateA)){
currentState = "B";
System.out.println(stateA + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i]=='b' && currentState.equals(stateA)){
currentState = "F";
System.out.println(stateA + " -- " + Inputted[i] + " --> " + stateF);
}

else if (Inputted[i] == 'a' && currentState.equals(stateB)){
currentState = "B";
System.out.println(stateB + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i] == 'b' && currentState.equals(stateB)){
currentState = "C";
System.out.println(stateB + " -- " + Inputted[i] + " --> " + stateC);
}

else if (Inputted[i]== 'b' && currentState.equals(stateF)){
currentState = "F";
System.out.println(stateF + " -- " + Inputted[i] + " --> " + stateF);
} else if (Inputted[i] == 'a' && currentState.equals(stateF)){
currentState = "B";
System.out.println(stateF + " -- " + Inputted[i] + " --> " + stateB);
}

else if (Inputted[i] == 'a' && currentState.equals(stateC)){
currentState = "D";
System.out.println(stateC + " -- " + Inputted[i] + " --> " + stateD);
} else if (Inputted[i] == 'b' && currentState.equals(stateC)){
currentState = "F";
System.out.println(stateC + " -- " + Inputted[i] + " --> " + stateF);
}

else if (Inputted[i] == 'a' && currentState.equals(stateD)){
currentState = "B";
System.out.println(stateD + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i] == 'b' && currentState.equals(stateD)){
currentState = "E";
System.out.println(stateD + " -- " + Inputted[i] + " --> " + stateE);
}

else if (Inputted[i] == 'a' && currentState.equals(stateE)){
currentState = "B";
System.out.println(stateE + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i] == 'b' && currentState.equals(stateE)){
currentState = "C";
System.out.println(stateE + " -- " + Inputted[i] + " --> " + stateC);
}

} if (currentState.equals(stateA) || currentState.equals(stateB) || currentState.equals(stateD) || currentState.equals(stateE)){
System.out.println("Input accepted");
keeprunning = false;
break;
} else if (currentState.equals(stateF) || currentState.equals(stateC)){
System.out.println("Input not accepted");
keeprunning = false;
break;
}

}
}

感谢您的帮助:D

最佳答案

只需将 while 循环 header 移至顶部,就在 keeprunning 声明之后:

Boolean keeprunning = true;
while(keeprunning){
...

并从 if-else 语句中删除以下代码:

keeprunning = false;
break;

这应该可以解决您所说的问题

<小时/>
import java.util.Scanner; 
public class Automata {
public static void main(String[] args) {

Boolean keeprunning = true;
while(keeprunning){
Scanner inputScanner = new Scanner(System.in);
System.out.println("Please enter your input");
String input = inputScanner.next();
char [] Inputted = input.toCharArray();

if (input.equalsIgnoreCase("Exit")){
keeprunning = false;
System.out.println("Exit now");
}
else{

String stateA = "A";
String stateB = "B";
String stateC = "C";
String stateD = "D";
String stateE = "E";
String stateF = "F";
String currentState = "A";


for (int i = 0; i < Inputted.length; i++){
if (Inputted[i]=='a' && currentState.equals(stateA)){
currentState = "B";
System.out.println(stateA + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i]=='b' && currentState.equals(stateA)){
currentState = "F";
System.out.println(stateA + " -- " + Inputted[i] + " --> " + stateF);
}

else if (Inputted[i] == 'a' && currentState.equals(stateB)){
currentState = "B";
System.out.println(stateB + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i] == 'b' && currentState.equals(stateB)){
currentState = "C";
System.out.println(stateB + " -- " + Inputted[i] + " --> " + stateC);
}

else if (Inputted[i]== 'b' && currentState.equals(stateF)){
currentState = "F";
System.out.println(stateF + " -- " + Inputted[i] + " --> " + stateF);
} else if (Inputted[i] == 'a' && currentState.equals(stateF)){
currentState = "B";
System.out.println(stateF + " -- " + Inputted[i] + " --> " + stateB);
}

else if (Inputted[i] == 'a' && currentState.equals(stateC)){
currentState = "D";
System.out.println(stateC + " -- " + Inputted[i] + " --> " + stateD);
} else if (Inputted[i] == 'b' && currentState.equals(stateC)){
currentState = "F";
System.out.println(stateC + " -- " + Inputted[i] + " --> " + stateF);
}

else if (Inputted[i] == 'a' && currentState.equals(stateD)){
currentState = "B";
System.out.println(stateD + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i] == 'b' && currentState.equals(stateD)){
currentState = "E";
System.out.println(stateD + " -- " + Inputted[i] + " --> " + stateE);
}

else if (Inputted[i] == 'a' && currentState.equals(stateE)){
currentState = "B";
System.out.println(stateE + " -- " + Inputted[i] + " --> " + stateB);
} else if (Inputted[i] == 'b' && currentState.equals(stateE)){
currentState = "C";
System.out.println(stateE + " -- " + Inputted[i] + " --> " + stateC);
}

} if (currentState.equals(stateA) || currentState.equals(stateB) || currentState.equals(stateD) || currentState.equals(stateE)){
System.out.println("Input accepted");

} else if (currentState.equals(stateF) || currentState.equals(stateC)){
System.out.println("Input not accepted");
}
}

}
}
}

关于java - 循环程序在完成检查后再次启动,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22827230/

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