C++将字符从静态数组复制到动态数组会添加一堆随机元素

Question

我有一个静态数组，但是当将值复制到动态数组时，我得到了一堆废话。我需要生成的动态数组正好是 8 个字符

unsigned char cipherText[9]; //Null terminated
cout<<cipherText<<endl;      //outputs = F,ÿi~█ó¡

unsigned char* bytes = new unsigned char[8];  //new dynamic array

//Loop copys each element from static to dynamic array.
for(int x = 0; x < 8; x++)
{       
    bytes[x] = cipherText[x];
}

cout<<bytes;     //output: F,ÿi~█ó¡²²²²½½½½½½½½ε■ε■

Answer 1

您需要更新代码以复制空终止符:

unsigned char* bytes = new unsigned char[9];  //new dynamic array

//Loop copys each element from static to dynamic array.
for(int x = 0; x < 9; x++)
{       
    bytes[x] = cipherText[x];
}

cout<<bytes;

这是假设 cipherText 实际上包含一个以 null 结尾的字符串。