java - 按特殊按钮退出

Question

这个问题已经有答案了:

How to close a Java Swing application from the code (9 个回答)

已关闭 9 年前。

我创建了一个自定义退出按钮，我希望在按下该按钮时代码终止。我怎样才能实现这一目标？

String[] button1 = {"exit", "next"};
//if next is pressed
if (code == JOptionPane.YES_OPTION) {
  JOptionPane.showMessageDialog(
              null, 
              "Knock knock" + "\nWho is there",
              "The Jasmin Project",
              JOptionPane.YES_NO_OPTION);
  int no = JOptionPane.showOptionDialog(null, "Want to view more?",
              "The Jasmin Project",
              JOptionPane.YES_NO_OPTION,
              JOptionPane.INFORMATION_MESSAGE,
              null,
              button1,
              button1[0]);
  //end code if exit is pressed            
  if (no == JOptionPane.NO_OPTION) {
     System.exit(1);
  }
}

Answer 1

您的错误在这一行:

String[] button1 = {"exit", "next"};

试试这个:

String[] button1 = {"next", "exit"};

第一个选项是"is"，第二个选项是“否”。