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c++ - 如何为类的每个接口(interface)单独定义一些函数?

转载 作者:行者123 更新时间:2023-11-30 03:53:01 31 4
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我正在学习COM,也是C++的初学者。我定义了三个接口(interface):

#include <objbase.h>

// pure abstract base class
interface IX : IUnknown{
virtual void __stdcall Fx() = 0; // pure virtual function
};

// pure abstract base class
interface IY : IUnknown{
virtual void __stdcall Fy() = 0; // pure virtual function
};

// pure abstract base class
interface IZ : IUnknown{
virtual void __stdcall Fz() = 0; // pure virtual function
};

extern "C"{
extern const IID IID_IX;
extern const IID IID_IY;
extern const IID IID_IZ;
}

然后我创建一个实现这些接口(interface)的类:

#include <iostream>
#include "IFace.h"

// COM component
class CA :
public IX,
public IY,
public IZ
{
public:
CA();
~CA();
virtual void __stdcall Fx(); // IX
virtual void __stdcall Fy(); // IY
virtual void __stdcall Fz(); // IZ
// IUnknown (this interface implemented by IX, IY and IZ)
virtual HRESULT __stdcall QueryInterface(const IID& iid, void** ppv);
virtual ULONG __stdcall AddRef();
virtual ULONG __stdcall Release();
private:
// Each interface has own counter (for convenience of debugging)
ULONG ix_counter;
ULONG iy_counter;
ULONG iz_counter;
};
...

我想为每个接口(interface)使用单独的实例计数器(为了调试方便)。在这种情况下,我必须如何定义 AddRef()Release() 函数?

我可以这样做:

ULONG __stdcall CA::AddRef(){
// increase interface counter here
}

但是对于我的 CA类。如果实例是 IX,那么我只需要增加 ix_counter 计数器。如果实例是 IY,那么我只需要增加 iy_counter 计数器,等等。

我试过这样的方法:

virtual HRESULT __stdcall QueryInterface(const IID& iid, void** ppv); // common implementation
virtual ULONG __stdcall IX::AddRef(); // for IX instances
virtual ULONG __stdcall IX::Release(); // for IX instances

virtual ULONG __stdcall IY::AddRef(); // for IY instances
virtual ULONG __stdcall IY::Release(); // for IY instances

virtual ULONG __stdcall IZ::AddRef(); // for IZ instances
virtual ULONG __stdcall IZ::Release(); // for IZ instances

代替

virtual ULONG __stdcall AddRef();
virtual ULONG __stdcall Release();

我也试过:

// This is wrong definitions:
ULONG __stdcall CA::IX::AddRef(){
return InterlockedIncrement(&ix_counter);
}

ULONG __stdcall CA::IX::Release(){
InterlockedDecrement(&ix_counter);
ULONG count = ix_counter + iy_counter + iz_counter;
if (0 == count) delete this;
return count;
}

代替

ULONG __stdcall CA::AddRef(){
// increase interface counter here
}

但是我最后的替换是错误的。

如何为每个接口(interface)单独定义 AddRef()Release() 函数?

最佳答案

您可以有一个特定于接口(interface)的计数器。您的代码可能如下所示:

// (interfaces defined)

template <typename T, typename Base>
class CUnknownWithCounterT :
public Base
{
public:
ULONG m_nCounter;

public:
CUnknownWithCounterT() :
m_nCounter(0)
{
}
ULONG __stdcall AddRef()
{
m_nCounter++;
return static_cast<T*>(this)->InternalAddRef();
}
ULONG __stdcall Release()
{
m_nCounter--;
return static_cast<T*>(this)->InternalRelease();
}
};

class CA :
public CUnknownWithCounterT<CA, IX>,
public CUnknownWithCounterT<CA, IY>,
public CUnknownWithCounterT<CA, IZ>
{
public:
ULONG m_nMainCounter;

public:
// QueryInterface as stuff...
ULONG __stdcall InternalAddRef()
{
return ++m_nMainCounter;
}
ULONG __stdcall InternalRelease()
{
return --m_nMainCounter;
}
};

准备开始:

CA A;
IX* pX = &A;
IY* pY = &A;
IZ* pZ = &A;
pY->AddRef();
pZ->AddRef();
pZ->AddRef();
_tprintf(_T("%d %d %d\n"),
A.CUnknownWithCounterT<CA, IX>::m_nCounter,
A.CUnknownWithCounterT<CA, IY>::m_nCounter,
A.CUnknownWithCounterT<CA, IZ>::m_nCounter,
0);
// 0 1 2

但是,您还需要分别覆盖 QueryInterface,因为它还以相应计数器需要递增的方式返回指针。

该实现将与 COM 兼容(m_nMainCounter 具有用于 COM 的计数器),问题是各个计数器在帮助您查找引用泄漏方面是否准确。如果它们在大多数情况下都有用,那么您当然可以将它们用于故障排除。

关于c++ - 如何为类的每个接口(interface)单独定义一些函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30345088/

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