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java - 这是正确的 MVC 设计吗?关于 MVC 设计和线程通信的建议

转载 作者:行者123 更新时间:2023-11-30 03:52:46 24 4
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最后一天我读了很多很多关于 MVC 模式的教程和博客。现在我已经基本理解了这个概念,但在我看来,每个教程都展示了在 Java 中实现此模式的另一个概念。所以我决定编写自己的应用程序,然后向技术更高的程序员寻求建议。 (边做边学是我的风格)。

所以我不想透露太多我最初的想法,但我会向你展示我的代码:

主类:

public class MainClass {enter code here
public static void main(String[] args){

MainController controller = new MainController();
controller.initView();
}
}

Controller 类:

public class MainController implements ActionListener{

private ExtractorStatics stat;
private MainView mainview;
private BusinessExtractor bExtractor;
private InfoboxTextPane infobox;
private BufferedImage logoGS;

public MainController(){
stat = new Statics();
model = new Model();
mainview = new MainView();
}
public void initView(){
if(mainview!=null){
mainview.setActionListener(this);
mainview.setItemListener(new ComboBoxItemListener(this));
mainview.setVisible(true);
}
}

@Override
public void actionPerformed(ActionEvent event) {
String command = event.getActionCommand();
if(command.equalsIgnoreCase(stat.SCAN_ACTION_COMMAND)){
this.quickScanButtonAction();
}
}


private void quickScanButtonAction(){
infobox = mainview.getInfobox();
ProcessingInformation information = model.quickScan();
InputStream informationStream = information.getInformationStream();
BufferedReader infoReader = new BufferedReader(
new InputStreamReader(informationStream));
String line;
try {
while ((line = infoReader.readLine()) != null) {
infobox.appendLine(line);
}

infoReader.close();
} catch (IOException e) {
e.printStackTrace();
}
System.out.println("End reached");
}
else
infobox.appendLine("Bitte Eingabe überprüfen.");
}
public void comboBoxChanged() {
//do some fancy stuff
}
}

class ComboBoxItemListener implements ItemListener{
MainController mc;
public ComboBoxItemListener(MainController mc){
this.mc=mc;
}
@Override
public void itemStateChanged(ItemEvent e) {
mc.comboBoxChanged();
}
}

MainView Class:

public class MainView extends JFrame {


private static final long serialVersionUID = 559229524422932258L;
private JPanel contentPane;
private JTextField txt_stichwort,txt_loc;
private JButton btn_quickscan;
private JTable table;
private JLabel label;
public InfoboxTextPane txtpn_infobox;
private String lineSep;
private final JComboBox<String> combobox;
/**
* Create the frame.
*/
public MainView() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException
| IllegalAccessException | UnsupportedLookAndFeelException e3) {
// TODO Auto-generated catch block
e3.printStackTrace();
}

lineSep=System.lineSeparator();
Statics stats=new Statics();



setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setBounds(100, 100, 800, 620);
contentPane = new JPanel();
contentPane.setBorder(new EtchedBorder(EtchedBorder.LOWERED, null, null));
setContentPane(contentPane);
contentPane.setLayout(null);


txt_subject= new JTextField();
txt_stichwort.setBounds(88, 47, 318, 20);
pan_suche.add(txt_stichwort);
txt_stichwort.setColumns(10);

combobox = new JComboBox<String>();
combobox.setBounds(88, 16, 318, 20);
pan_suche.add(combobox);
combobox.setModel(new DefaultComboBoxModel(new String[] {"Item1", "Item2"}));

txt_loc = new JTextField();
txt_loc.setBounds(88, 79, 318, 20);
pan_suche.add(txt_loc);
txt_loc.setColumns(10);



btn_quickscan = new JButton("Quick Scan");
btn_quickscan.setActionCommand(stats.SCAN_ACTION_COMMAND);
btn_quickscan.setBounds(10, 23, 130, 30);
pan_dos.add(btn_quickscan);

//a few more buttons that have other action commands defined by statics
//more labels and other GUI components


}
public InfoboxTextPane getInfobox(){
return this.txtpn_infobox;
}
public String getSearchSubject(){
return this.txt_stichwort.getText();
}

public String getSearchLocation(){
return this.txt_loc.getText();
}
public String getSearchWebsite(){
return (String)this.combobox.getSelectedItem();
}
public JComboBox<String> getComboBox(){
return this.combobox;
}
public JLabel getLogoLabel(){
return this.label;
}

public void setActionListener(ActionListener al){
try {

btn_quickscan.addActionListener(al);
} catch (NullPointerException e) {
e.printStackTrace();
}
}

public void setItemListener(ItemListener il){
this.combobox.addItemListener(il);
}
}

模型类:

public class Model {
private ExecutorService exeService;

public Model(){
exeService =Executors.newCachedThreadPool();
}

public ProcessingInformation quickScan(){
QuickScanRoutine qs = new QuickScanRoutine();
Future<String> result = exeService.submit(qs);
return qs.getProcessingInformation();
}

}

例程类(可调用):

public class QuickScanRoutine implements Callable<String> {
private ProcessingInformation pi;
private BufferedWriter writer;



public QuickScanRoutine(){
pi = new ProcessingInformation();
PipedOutputStream pos = new PipedOutputStream();
PipedInputStream pis;
writer = new BufferedWriter(new OutputStreamWriter(pos));

try {
pis = new PipedInputStream(pos);
pi.setInformationStream(pis);
} catch (IOException e) {
e.printStackTrace();
}

}

public ProcessingInformation getProcessingInformation(){
return this.pi;
}

@Override
public String call() throws Exception {

//ofcourse this isnt the real purpose of this Class but I want to `demonstrate writing to the stream`

for(int i =0; i<100;i++){
writer.write("Hello");
writer.newLine();
writer.flush();
}
writer.close();
return "Routine has been executed sucessfully!";
}

}

处理信息:

public class ProcessingInformation {
PipedInputStream informationStream,resultDataStream;

public void setInformationStream(PipedInputStream info) {
this.informationStream = info;
}
public void setResultDataStream(PipedInputStream data){
//I will need this stream for further tasks
this.resultDataStream = data;
}

public InputStream getInformationStream(){
if(informationStream!=null){
return informationStream;
}
else
return null;
}

public InputStream getResultDataStream(){
if(informationStream!=null){
return informationStream;
}
else
return null;
}
}

我尝试尽可能缩短代码,但尝试将其放在上下文中,以便您可以理解整个结构。我的主要问题是:

  • 这是正确的 MVC 设计吗?
  • 这是从该模型线程到 View 进行通信的合适方式吗? (管道流)

这些是我的主要问题,但我很感激并愿意接受您的所有建议。

最佳答案

我同意 Abhi Beckert 在某些方面的回答 - 通常如下:

  1. 模型与模型以外的任何对象进行通信都是 Not Acceptable 。
  2. View 应该只与其他 View 对象通信,而不了解 Controller 。

此外, Controller 必须了解有关 View 组成的任何信息,因为这会将 Controller 和 View 耦合起来。这种耦合意味着,如果您需要更改 View 表示,或者为此向用户提供各种数据表示的选择,您将必须为每个表示编写一个新的 Controller 。让我通过一个例子来具体说明这一点。

当您在 MS-Word 等文字处理器中打开 Word 文档时,页面可以采用各种布局,例如纵向、横向、打印和 Html。在每种布局中,可见的用户元素都不同。但数据是一样的。因此,解决该问题的最合乎逻辑的方法是:

  • 让 Controller 向模型发送命令以更新相应的 View 。
  • 让 Controller 查询模型以获取数据,并将获取的数据简单地传递给 View 进行渲染。

我浏览了您发布的代码并确定您的 Controller 知道 View 的内容,例如MainController 调用 MainView.getinfobox()。根据上述解释,您可能想要更改它。

关于与使用PipedStream发送数据相关的第二个问题,我没有发现其中有任何技术上的错误 - 因为流也是数据的容器。但是,到目前为止,我个人还没有看到或遇到过遵循这种模式的设计或代码片段。

希望这有帮助

关于java - 这是正确的 MVC 设计吗?关于 MVC 设计和线程通信的建议,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23973673/

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