java spring上下文:property-placeholder - set properties paths from placeholder

Question

<context:property-placeholder
    location="a.properties,b.properties"
    ignore-unresolvable="true"/>

结果:两个属性文件均已加载

<context:property-placeholder
    location="${properties_location}"
    ignore-unresolvable="true"/>

其中properties_location是“a.properties,b.properties”

result: Exception in thread "main" org.springframework.beans.factory.BeanInitializationException: Could not load properties; nested exception is java.io.FileNotFoundException: class path resource [a.properties,b.properties] cannot be opened because it does not exist

编辑:${properties_location} 设置如下:

System.getProperties().setProperty("properties_location", "a.properties,b.properties");
ApplicationContext ctx = new GenericXmlApplicationContext("context.xml");
...

如何以第二种方式初始化我的应用程序？在占位符中定义所有属性文件的路径。

Answer 1

您必须将其更改为:

<context:property-placeholder
location="classpath:a.properties,
          classpath:b.properties"
ignore-unresolvable="true"/>