android - 联系人姓名和号码正确时无法获取正确的电子邮件

Question

我是 android 的新手，每次我使用下面的代码时，我都想获取联系人列表中现有联系人的电子邮件，但我无法获取联系人的确切电子邮件，而是任何随机电子邮件。请帮助我更正此代码，我将非常感激。

 public void fetchingContacts(Context context) {

            Uri uri = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
            ContentResolver cr = context.getContentResolver();
            Cursor crsr = cr.query(uri, null, null, null, null);

            crsr.moveToFirst();

            if (crsr.getCount() > 0) {
                while (crsr.moveToNext()) {
                    ID = crsr
                            .getString(crsr
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Phone._ID));
                    id = crsr.getString(crsr.getColumnIndex(BaseColumns._ID));
                    NAME = crsr
                            .getString(crsr
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    NUMBER = crsr
                            .getString(crsr
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

                    arylist_contact_id.add(ID);
                    arylist_all_number.add(NUMBER);
                    arylist_all_names.add(NAME);
                    // ////////////



                    Cursor emailCur = cr.query(
                            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                            null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                    + " = " + id, null, null);

                    while (emailCur.moveToNext()) {
                        email = emailCur
                                .getString(emailCur
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                        Log.v("fetchingEMAIL ---  ", email);

                    }
                    emailCur.close();


                    Log.v("IN do while :: name and number ", ID + " , id :" + id
                            + "  " + NAME + " : " + NUMBER + "  :  " + email);
                } 

            }
            crsr.close();
        }

Answer 1

            Cursor emailCur = cr.query(
                    ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                    null,
                    ContactsContract.CommonDataKinds.Email.CONTACT_ID
                            + " = ?", new String[] { id }, null);
            while (emailCur.moveToNext()) {
            String  email = emailCur
                        .getString(emailCur
                                .getColumnIndex(ContactsContract.CommonDataKinds.Email.ADDRESS));

            }
            emailCur.close();

以上是有助于正确获取电子邮件的查询，我的 friend ，它对我有用...希望尝试一下。