gpt4 book ai didi

java - 通用平等测试

转载 作者:行者123 更新时间:2023-11-30 03:50:41 24 4
gpt4 key购买 nike

我想检查两个Java对象是否相等。此检查也适用于数组。我写的是:

/** Check if two Java objects are equal. */
private static <T> boolean equal (T a, T b)
{
if (a == null)
if (b == null)
return true;
else
if (b.getClass().isArray())
return Arrays.equals(b, a);
else
return b.equals(a);
else
if (a.getClass().isArray())
return Arrays.equals(a, b);
else
return a.equals(b);
}

但是调用Arrays.equals无法编译并出现以下错误:

no suitable method found for equals(T,T)

我该如何解决这个问题?

最佳答案

如果你查看java.util.Arrays.deepEquals0(Object, Object)

可以看到下面的代码

static boolean deepEquals0(Object e1, Object e2) {
assert e1 != null;
boolean eq;
if (e1 instanceof Object[] && e2 instanceof Object[])
eq = deepEquals ((Object[]) e1, (Object[]) e2);
else if (e1 instanceof byte[] && e2 instanceof byte[])
eq = equals((byte[]) e1, (byte[]) e2);
else if (e1 instanceof short[] && e2 instanceof short[])
eq = equals((short[]) e1, (short[]) e2);
else if (e1 instanceof int[] && e2 instanceof int[])
eq = equals((int[]) e1, (int[]) e2);
else if (e1 instanceof long[] && e2 instanceof long[])
eq = equals((long[]) e1, (long[]) e2);
else if (e1 instanceof char[] && e2 instanceof char[])
eq = equals((char[]) e1, (char[]) e2);
else if (e1 instanceof float[] && e2 instanceof float[])
eq = equals((float[]) e1, (float[]) e2);
else if (e1 instanceof double[] && e2 instanceof double[])
eq = equals((double[]) e1, (double[]) e2);
else if (e1 instanceof boolean[] && e2 instanceof boolean[])
eq = equals((boolean[]) e1, (boolean[]) e2);
else
eq = e1.equals(e2);
return eq;
}

所以我认为你需要做类似的事情。

关于java - 通用平等测试,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24531740/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com