c++ - cstring 数组有问题

Question

我在使用数组时遇到问题。我收到以下错误

In function ‘int main(int, const char**)’:
75: error: cannot convert ‘char*’ to ‘char (*)[81]’ for argument ‘1’                                                                  ion(char (*)[81], OneItem*, int&, int&)’
 In function ‘void parseInformation(char (*)[81], OneItem*, int&, in
164: error: ISO C++ forbids comparison between pointer and integer
166: error: incompatible types in assignment of ‘const char [2]’ to
169: error: ISO C++ forbids comparison between pointer and integer
174: error: ISO C++ forbids comparison between pointer and integer
174: error: ISO C++ forbids comparison between pointer and integer
176: error: invalid conversion from ‘char*’ to ‘char’

代码与行号不一致。我已经尝试了很多东西，用谷歌搜索了一些东西仍然没有找到解决方案。

const int MAX_CHARACTERS = 80;
    const int MAX_INVENTORY = 12;

    typedef char OneLine[MAX_CHARACTERS + 1];
    struct OneItem
    {
        char product[MAX_CHARACTERS + 1];
        int quantity;
        float unitPrice;
        float totalPrice;
    };



    int main( const int argc, const char* argv[] )
    {

        OneLine fileName;
        ifstream inFile;

        OneLine readLine;
        OneItem inventory[MAX_INVENTORY];


        int readLineIndex;
        int structureCounter = 0;
        int averageQuantity;
        float averagePrice;
        float averageTotalPrice;

        displayIntroduction();

        getFileName( argc, argv, fileName );
        if (!inFile)
        {
            cout << "File not found: " << fileName << endl;
        }
        else 
        {
            inFile.open(fileName);
            while(!inFile.getline(readLine, MAX_CHARACTERS, '\n').eof())
            {
                if (structureCounter < MAX_INVENTORY)
                {
                    parseInformation(readLine,inventory, readLineIndex, structureCounter);
                }
            }

void parseInformation(OneLine readLine[],OneItem inventory[], int & readLineIndex, int & structureCounter)
{
    int tempIndex = 0;
    int valueCounter = 0;
    OneLine tempArray;
    while(readLine[readLineIndex] != '\n')
    {
        tempArray = "\0";


        while(readLine[readLineIndex] == ' ')
        {
            readLineIndex += 1;

        }
        while(readLine[readLineIndex] != ' ' && readLine[readLineIndex] != '\n')
        {   
            tempArray[tempIndex] = readLine[readLineIndex];
            tempIndex += 1;
            readLineIndex += 1;
        }
        if(valueCounter == 0)
        {
            for(int i = 0; i <= strlen(tempArray); i++)
            {
                inventory[structureCounter].product[i] = tempArray[i];
            }
            valueCounter += 1;
        }
        else if(valueCounter == 1)
        {
            inventory[structureCounter].quantity = atoi(tempArray);
            valueCounter += 1;
        }
        else
        {
            inventory[structureCounter].unitPrice = atof(tempArray);
            structureCounter += 1;
        }



    }
    return;

Answer 1

您对 parseInformation 的定义是错的。它说 readLine应该是 OneLine 的数组, 但它只需要一个 OneLine .应该是:

void parseInformation(OneLine readLine,OneItem inventory[], int & readLineIndex, int & structureCounter)

这会导致您收到所有错误，因为您使用单个 OneLine 调用该函数，不是数组。在你比较的函数内部 readLine[readLineIndex]带有一个字符，需要 readLine是字符数组，而不是 OneLine 的数组.

OneLine typedef 已经使它成为一个数组，你不需要添加 []到参数声明。