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c++ - Boost.Graph 库:如何使用 boost::is_isomorphism 命名顶点

转载 作者:行者123 更新时间:2023-11-30 03:45:48 25 4
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此问题类似于 BGL: Example of isomorphism with vertex invariants

我正在研究 Boost.Graph tutorial在两个没有属性的图上调用 boost::is_isomorphism 很容易。但是当顶点现在有了名称时,我无法让它工作。

此代码显示:

  • 我如何创建具有命名顶点的路径图(不重要)
  • 我的测试代码
  • 我用命名顶点测试同构的函数

下面是我如何创建带有命名顶点的路径图(这并不重要,但为了完成显示):

boost::adjacency_list<
boost::vecS,
boost::vecS,
boost::undirectedS,
boost::property<
boost::vertex_name_t, std::string
>
>
create_named_vertices_path_graph(
const std::vector<std::string>& names
) noexcept
{
auto g = create_empty_undirected_named_vertices_graph();
if (names.size() == 0) { return g; }

auto vertex_name_map
= get( //not boost::get
boost::vertex_name,
g
);

auto vd_1 = boost::add_vertex(g);
vertex_name_map[vd_1] = *names.begin();
if (names.size() == 1) return g;

const auto j = std::end(names);
auto i = std::begin(names);
for (++i; i!=j; ++i) //Skip first
{
auto vd_2 = boost::add_vertex(g);
vertex_name_map[vd_2] = *i;
const auto aer = boost::add_edge(vd_1, vd_2, g);
assert(aer.second);
vd_1 = vd_2;
}
return g;
}

这是我的测试:

void is_named_vertices_isomorphic_demo() noexcept
{
const auto g = create_named_vertices_path_graph(
{ "Alpha", "Beta", "Gamma" }
);
const auto h = create_named_vertices_path_graph(
{ "Alpha", "Gamma", "Beta" }
);
assert( is_named_vertices_isomorphic(g,g));
assert(!is_named_vertices_isomorphic(g,h));
}

我想或多或少地编写函数 is_named_vertices_isomorphic(注意:这将编译,但测试失败,灵感来自 BGL: Example of isomorphism with vertex invariants):

template <typename graph1, typename graph2>
bool is_named_vertices_isomorphic_correct(
const graph1& g,
const graph2& h
) noexcept
{
auto ref_index_map = get(boost::vertex_index, g);
using vd = typename boost::graph_traits<graph1>::vertex_descriptor;
std::vector<vd> iso(boost::num_vertices(g));
return boost::isomorphism(g,h,
boost::isomorphism_map(
make_iterator_property_map(iso.begin(), ref_index_map, iso[0])
)
);
}

看问题BGL: Example of isomorphism with vertex invariants让我想到了这个:

template <typename Graph>
std::string discrete_vertex_invariant(
const typename boost::graph_traits<Graph>::vertex_descriptor& vd,
const Graph &g
)
{
const auto name_map = get(boost::vertex_name,g);
return name_map[vd];
}

template <typename Graph>
class discrete_vertex_invariant_functor
{
using vertex_t = typename boost::graph_traits<Graph>::vertex_descriptor;
const Graph& m_graph;
public:
using result_type = std::string;
using argument_type = vertex_t;
discrete_vertex_invariant_functor(const Graph &g) : m_graph(g) {}
result_type operator()(const vertex_t& vd) const
{
return discrete_vertex_invariant(vd,m_graph);
}
result_type max() const
{
return "";
}
};

//helper function to help with argument deduction
template <typename Graph>
discrete_vertex_invariant_functor<Graph> make_discrete_vertex_invariant(
const Graph &g
)
{
return discrete_vertex_invariant_functor<Graph>(g);
}

template <typename graph1, typename graph2>
bool is_named_vertices_isomorphic_correct(
const graph1& g,
const graph2& h
) noexcept
{
auto ref_index_map = get(boost::vertex_index, g);
using vd = typename boost::graph_traits<graph1>::vertex_descriptor;
std::vector<vd> iso(boost::num_vertices(g));
return boost::isomorphism(
g,
h,
isomorphism_map(
make_iterator_property_map(iso.begin(), ref_index_map, iso[0])
).vertex_invariant1(make_discrete_vertex_invariant(g))
.vertex_invariant2(make_discrete_vertex_invariant(h))
);
}

两种解决方案都失败了。谁能帮帮我?

最佳答案

看来您并不追求同构,至少严格按照定义是这样。

如果您实际上希望比较图而不考虑顶点索引顺序,但严格比较顶点名称,则必须将名称映射到整数类型(因为 max_vertex_invariant 值应为无符号整数)。

这里有一个简单的实现方法:

template <typename graph1, typename graph2>
bool is_named_vertices_isomorphic/*_correct*/(const graph1 &g, const graph2 &h) noexcept {
auto ref_index_map = get(boost::vertex_index, g);
using vd = typename boost::graph_traits<graph1>::vertex_descriptor;
std::vector<vd> iso(boost::num_vertices(g));

VertexInvariant::Map shared_names;
VertexInvariant inv1 { g, shared_names };
VertexInvariant inv2 { h, shared_names };

inv1.collect_names();
inv2.collect_names();

return boost::isomorphism(g, h,
boost::isomorphism_map(make_iterator_property_map(iso.begin(), ref_index_map))
.vertex_invariant1(inv1)
.vertex_invariant2(inv2)
);
}

我还没有让事情变得通用,因为它会分散注意力。

For good form, you'd need to use boost::property_maps::property_traits<boost::property_map<graph1, boost::vertex_name_t>::const_type>::value_type or similar, and check that the resultant type is actually compatible for comparison between graph1 and graph1 etc.

To be "actually" generic you'd want to pass in a deduced property map instead of boost::get(boost::vertex_name, g) and so on.

To be honest, I feel that this doesn't make much sense for such semantic-laden things as the iso-morphism invariants. You can obviously make things as generic as you need them to be for your application.

struct VertexInvariant {
using Map = std::map<std::string, size_t>;
Graph const& _graph;
Map& _mappings;

using result_type = size_t;
using argument_type = Graph::vertex_descriptor;

size_t operator()(argument_type u) const {
return _mappings.at(boost::get(boost::vertex_name, _graph, u));
}
size_t max() const { return _mappings.size(); }

void collect_names() {
for (auto vd : boost::make_iterator_range(boost::vertices(_graph))) {
size_t next_id = _mappings.size();
auto ins = _mappings.insert({ boost::get(boost::vertex_name, _graph, vd), next_id});
if (ins.second) {
//std::cout << "Mapped '" << ins.first->first << "' to " << ins.first->second << "\n";
}
}
}
};

helper 在哪里VertexInvariant定义为:

struct VertexInvariant {
using Map = std::map<std::string, size_t>;
Graph const& _graph;
Map& _mappings;

using result_type = size_t;
using argument_type = Graph::vertex_descriptor;

size_t operator()(argument_type u) const {
return _mappings.at(boost::get(boost::vertex_name, _graph, u));
}
size_t max() const { return _mappings.size(); }

void collect_names() {
for (auto vd : boost::make_iterator_range(boost::vertices(_graph))) {
size_t next_id = _mappings.size();
auto ins = _mappings.insert({ boost::get(boost::vertex_name, _graph, vd), next_id});
if (ins.second) {
//std::cout << "Mapped '" << ins.first->first << "' to " << ins.first->second << "\n";
}
}
}
};

完整演示

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#include <boost/graph/adjacency_list.hpp>
#include <boost/graph/isomorphism.hpp>
#include <boost/graph/vf2_sub_graph_iso.hpp>
#include <boost/graph/graph_utility.hpp>

using Graph = boost::adjacency_list<boost::vecS, boost::vecS, boost::directedS,
boost::property<boost::vertex_name_t, std::string> >;

Graph create_empty_undirected_named_vertices_graph() { return {}; }

Graph create_named_vertices_path_graph(const std::vector<std::string> &names) noexcept {
auto g = create_empty_undirected_named_vertices_graph();
if (names.size() == 0) {
return g;
}

auto vertex_name_map = get(boost::vertex_name, g); // not boost::get

auto vd_1 = boost::add_vertex(g);
vertex_name_map[vd_1] = *names.begin();
if (names.size() == 1)
return g;

const auto j = std::end(names);
auto name_it = std::begin(names);
for (++name_it; name_it != j; ++name_it) // Skip first
{
auto vd_2 = boost::add_vertex(g);
vertex_name_map[vd_2] = *name_it;
const auto aer = boost::add_edge(vd_1, vd_2, g);
assert(aer.second);
vd_1 = vd_2;
}
return g;
}

//////////////////////////////////////// {{{
namespace {

struct VertexInvariant {
using Map = std::map<std::string, size_t>;
Graph const& _graph;
Map& _mappings;

using result_type = size_t;
using argument_type = Graph::vertex_descriptor;

size_t operator()(argument_type u) const {
return _mappings.at(boost::get(boost::vertex_name, _graph, u));
}
size_t max() const { return _mappings.size(); }

void collect_names() {
for (auto vd : boost::make_iterator_range(boost::vertices(_graph))) {
size_t next_id = _mappings.size();
auto ins = _mappings.insert({ boost::get(boost::vertex_name, _graph, vd), next_id});
if (ins.second) {
//std::cout << "Mapped '" << ins.first->first << "' to " << ins.first->second << "\n";
}
}
}
};


}
//////////////////////////////////////// }}}

template <typename graph1, typename graph2>
bool is_named_vertices_isomorphic/*_correct*/(const graph1 &g, const graph2 &h) noexcept {
auto ref_index_map = get(boost::vertex_index, g);
using vd = typename boost::graph_traits<graph1>::vertex_descriptor;
std::vector<vd> iso(boost::num_vertices(g));

VertexInvariant::Map shared_names;
VertexInvariant inv1 { g, shared_names };
VertexInvariant inv2 { h, shared_names };

inv1.collect_names();
inv2.collect_names();

return boost::isomorphism(g, h,
boost::isomorphism_map(make_iterator_property_map(iso.begin(), ref_index_map))
.vertex_invariant1(inv1)
.vertex_invariant2(inv2)
);
}

void is_named_vertices_isomorphic_demo() noexcept {
const auto g = create_named_vertices_path_graph({ "Alpha", "Beta", "Gamma" });
std::cout << "\n==== g:\n"; boost::print_graph(g, boost::get(boost::vertex_name, g));
const auto h = create_named_vertices_path_graph({ "Alpha", "Gamma", "Beta" });
std::cout << "\n==== h:\n"; boost::print_graph(h, boost::get(boost::vertex_name, h));

assert(is_named_vertices_isomorphic(g, g));
assert(!is_named_vertices_isomorphic(g, h));
}

int main() { is_named_vertices_isomorphic_demo(); }

打印:

==== g:
Alpha --> Beta
Beta --> Gamma
Gamma -->

==== h:
Alpha --> Gamma
Gamma --> Beta
Beta -->

关于c++ - Boost.Graph 库:如何使用 boost::is_isomorphism 命名顶点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34501216/

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