c++ - 使用 GPGME 生成 key 时出错

Question

我正在尝试使用 GPGME 生成一个新 key ，但遗憾的是我无法使以下代码工作:

 std::string def = "<GnupgKeyParms format='internal'>"
                    " Key-Type: default "
                    " Subkey-Type: default"
                    " Name-Real: Joe Tester"
                    " Name-Comment: with stupid passphrase"
                    " Name-Email: joe2@foo.bar"
                    " Expire-Date: 0"
                    " Passphrase: abc"
                    " </GnupgKeyParms>";

            gpgme_error_t error = gpgme_op_genkey(mContext, def.c_str(), NULL, NULL);

            if(GPG_ERR_INV_VALUE  == error){
                std::cout << "Value error";
            }
            if(GPG_ERR_NOT_SUPPORTED == error){
                std::cout << "Not supported error";
            }
            if(GPG_ERR_GENERAL  ==  error){
                std::cout << "general error";
            }
            if(error == GPG_ERR_NO_ERROR){
                gpgme_genkey_result_t res = gpgme_op_genkey_result(mContext);
                if(res->primary && res->sub){
                    result = true;
                }
            }
        }

条件 error == GPG_ERR_NO_ERROR 不成立。事实上，没有一个错误检查条件是。我的调试器只是告诉我 error 的值为 117440567。初始化如下所示:

gpgme_engine_info_t info;
    gpgme_error_t  error;
    const char * CONFIG_DIR = "/";

    // Initializes gpgme
    gpgme_check_version(NULL);

    // Initialize the locale environment.
    setlocale(LC_ALL, "");
    gpgme_set_locale(NULL, LC_CTYPE, setlocale(LC_CTYPE, NULL));
#ifdef LC_MESSAGES
    gpgme_set_locale(NULL, LC_MESSAGES, setlocale(LC_MESSAGES, NULL));
#endif
    error = gpgme_set_engine_info(GPGME_PROTOCOL_OpenPGP, NULL,
                                  CONFIG_DIR);
    if(error)
        return false;
    error = gpgme_new(&mContext);
    if(error)
        return false;
    // Check OpenPGP
    error = gpgme_engine_check_version(GPGME_PROTOCOL_OpenPGP);
    if(error)
        return false;
    // load engine info
    error = gpgme_get_engine_info(&info);
    if(error)
        return false;
    while(info && info->protocol != gpgme_get_protocol(mContext)) {
        info = info->next;
    }     

    if(error)
        return false;    

我在这里没有收到任何错误。我完全能够使用 GnuPG 命令行创建 key 。那么在使用 GPGME 创建 key 时出现的这个奇怪错误是什么意思呢？

UDAPTE:

感谢 Auges 的回答，我现在可以说它是 GPG_ERR_INV_VALUE，这意味着参数字符串格式错误。但为什么？我必须用空格以外的东西来分隔值吗？

更新

我更改了内部引号

GnupgKeyParms format=\"internal\"

但现在我得到一个GPG_ERR_GENERAL。

更新:

字符串现在看起来像:

std::string def = "<GnupgKeyParms format=\"internal\"> \n"
                    " Key-Type: default \n"
                    " Subkey-Type: default \n"
                    " Name-Real: Joe Tester3 \n"
                    " Name-Comment: with stupid passphrase \n"
                    " Name-Email: joe3@foo.bar \n"
                    " Expire-Date: 0 \n"
                    " Passphrase: abc \n"
                    " </GnupgKeyParms>";

但应用程序卡在 gpgme_op_genkey。

Answer 1

如果你看看documentation您发现 gpgme_errot_t 无法与错误代码进行比较:

... the error value can not be directly compared against an error code, but the accessor functions described below must be used. However, it is guaranteed that only 0 is used to indicate success (GPG_ERR_NO_ERROR), and that in this case all other parts of the error value are set to 0, too.

error 的值仍然应该为零。我帮不了你了

您可以尝试使用 gpgme_err_code 找出发生的错误。