java - 使用 JAVA 获取给定 XML 元素的属性

Question

这是 XML 文件:

<TestCase name="SearchPromotions" type="DDTC" recovery="false" datatable="HsbcDemoSearchPromotionstestCaseSpecificVirtualDatatable" position="0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:noNamespaceSchemaLocation="file://C:/New folder/VTAF/base-qa-3.0.5.2/generator/xsd/TestCase.xsd">

    <SelectedDataTableNames name="SearchData"> </SelectedDataTableNames>

    <Open page="hsbc"  ms="5000"  />
    <Click object="hsbc.Personal_Link"  />
    <Click object="hsbc.CreditCard_tab"  />
    <Call businessComponent="Global.Verify_Search">
       <Param name="HotelName_Param" value="@SearchData_link" />
    </Call>
    <CheckElementPresent object="hsbc.Img_Hotel_logo"  Identifire="Hotel_Name_PARAM:@SearchData_ResultHotelName"  fail="true"  customErrorMessage="Searched hotel name is not present in the page."  />
</TestCase>

这是从指定元素获取属性的java代码。如果我尝试运行它会给出 NullpointException。我不知道缺少什么或出了什么问题。请任何人都可以帮助我。我已经注释了发生异常的行:

File fXmlFile = new File("SearchPromotions.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();

Element docEle = doc.getDocumentElement();
NodeList nl = docEle.getChildNodes();

if (nl != null && nl.getLength() > 0) {
    for (int i = 0; i < nl.getLength(); i++) {
        if (nl.item(i).getNodeType() == Node.ELEMENT_NODE) {
            Element ele = (Element) nl.item(i);

            switch(ele.getNodeName()){
                case "Click":
                    System.out.println(ele);
                    //----------------
                    System.out.println(ele.getAttributes().getNamedItem("page").getNodeValue());
                    //----------------
                    break;
                default:
                    break;
            }
        }
    }
}

Answer 1

您正在尝试获取 Click 元素的 page 属性，但它只包含 object 属性。

因此，当执行 ele.getAttributes().getNamedItem("page").getNodeValue() getNamedItem("page") 将返回 null.