c++ - 猜谜游戏的问题

Question

我需要做一个猜谜游戏，程序会生成一个随机数，用户必须猜测这个数字。如果用户猜中数字少于 10 次，程序会向他们表示祝贺，并让他们知道他们猜不到 10 次。如果他们的猜测超过 10 次，那么它会让他们知道它超过 10 次，等等。

我面临的问题是，例如，如果用户在 3 次尝试中猜到了数字，然后决定用一个全新的其他数字再次玩，这次在 8 次尝试中猜到了，而不是仍然祝贺他们因为它少于 10 次尝试，所以它计算了上一场比赛的 3 次尝试。这导致程序告诉他们他们已经超过 10 次尝试，即使他们没有。我不知道如何解决这个问题。到目前为止我完成的代码如下:

int main()
{
   srand(time(0));
   int guess;
   int number;
   char selection = 'y';
   int numberOfGuesses=0;

 while(selection == 'y' || selection == 'Y')
 {
      number = rand() % 1000 + 1;

      cout << "I have a number between 1 and 1000.\nCan you guess my number?\nPlease type your first guess: ";
      cin >>guess;

      do
      {
         if(number > guess)
         {
            cout << "Too low. Try again: " << endl;
            cin >> guess;
            numberOfGuesses++;
         }
         if (number < guess)
         {
            cout << "Too high. Try again: " << endl;
            cin >> guess;
            numberOfGuesses++;
         }

      } 

      while(number != guess);

      if(numberOfGuesses < 9)
      {
            cout << "You guessed the number in less than 10 guesses!\n Would you like to play again (y or n)?";
            cin >> selection;
      }
      else if(numberOfGuesses > 9)
      {
            cout << "You guessed the number\n Would you like to play again (y or n)?";
            cin >> selection;
      }

      else if(numberOfGuesses == 9)
      {
            cout << "You guessed the number.\n Would you like to play again (y or n)?";
            cin >> selection;
      }

  }

   return 0;
 }

Answer 1

问题是您没有重置计数器。只需将 int numberOfGuesses=0; 放在 while 循环中:

while(selection == 'y' || selection == 'Y')
{
    int numberOfGuesses=0;
    ....
}