java - 斐波那契数列检测器 Java

Question

我的 Java 入门类(class)的斐波那契数列程序遇到问题。仅当我按升序输入数字时它才有效。

目标:必须使用 while 循环，必须检测数字是否是斐波那契数，并且必须检测序列中数字的顺序。如果它不是斐波那契数，则必须如此说明，并说明它位于哪些数字之间。程序还必须不断要求输入数字，直到用户退出

输出示例:

Please input a number for analysis >> 2
2 is a fibonacci number whose order in the sequence is 4
Please input a number for analysis >> 53
53 is not a fibonacci number 
However, it lies between the Fibonacci numbers 34 (order:10) and 55 (order:11)

我的问题:该程序仅在我按升序键入输入数字时才起作用。例如，如果我输入 5，它会告诉我这是一个带有 seq 的 fib 数字。的 6。但是当我输入 2 时，它说这不是斐波那契数，但它位于斐波那契数 3(阶数:5)和 5(阶数:6)之间。当我输入 55 时，它告诉我这是一个虚假数字。但是我无法输入任何低于 55 的数字而不显示错误的输入。

我认为问题出在 else if 语句上，可能是 (fibnext != testnum)。或者也许是计数？谁能指出我可能出现问题的方向？

import java.util.Scanner;

public class Fibonacci
{
    public Fibonacci()
    {
        int fibhigh = 1;
        int fiblow = 0;
        int count = 2;
        int fibnext = 0;
        Scanner input = new Scanner(System.in);
        boolean quit = false;

        System.out.println("Welcome to Fibonacci Sequence Dectector");
        while(!false)
        {
            System.out.print("Please input a number for analysis >> ");
            int testnum = input.nextInt();

            if(testnum < 0)
            {
                System.out.println("Please enter a positive number");
                continue;
            }
            while(fibnext < testnum)
            {
                fibnext = fibhigh + fiblow;
                fiblow = fibhigh;
                fibhigh = fibnext;
                count++;
            }
            if(fibnext == testnum)
            {
                System.out.println(testnum + " is a fibonacci number whose order in the sequence is " + count);
            }
            else if(fibnext != testnum) System.out.println(testnum + " is not a fibonacci number \nHowever, it lies between the Fibonacci numbers " + fiblow + " (order:" + (count - 1) + ") and " + fibhigh + " (order:" + count + ")");
        }
    }
}

Answer 1

你永远不会重置变量int fibhigh = 1，fiblow = 0，count = 2，fibnext = 0;

您应该移动此代码片段

int fibhigh = 1;
int fiblow = 0;
int count = 2;
int fibnext = 0;

在循环开始时:

while (!false) {  }