c++ - 将圆分成n等份得到每个分割点的坐标

Question

我已阅读 this我尝试用 C++ 实现它，但输出却大不相同。我不知道出了什么问题。我使用的代码:

double cordinate_print()
{
    int x, y;
    int number_of_chunks = 5;
    double angle=0;
    double x_p[5] ; // number of chunks 
    double y_p[5]; // number of chunks 
    //double x0, y0 = radious;
    double rad = 150;

    for (int i = 0; i < number_of_chunks; i++)
    {
        angle = i * (360 / number_of_chunks);
        float degree = (angle * 180 / M_PI);
        x_p[i] = 0 + rad * cos(degree);
        y_p[i] = 0 + rad * sin(degree);
        //printf("x-> %d y-> %d \n", x_p[i], y_p[i]);
        cout << "x -> " << x_p[i] << "y -> " << y_p[i] << "\n";
    }

    //printing x and y values

    printf("\n \n");

    return 0;

}

输出

x -> 150 y -> 0
x -> -139.034 y -> -56.2983
x -> 107.74 y -> 104.365
x -> -60.559 y -> -137.232
x -> 4.77208 y -> 149.924

正确的输出

(150,0)

(46,142)

(-121,88)

(-121,-88)

(46,-142)

Answer 1

将度数转换为弧度的问题

float degree = (angle * 180 / M_PI);

正确的换算公式是

float radian = (angle * M_PI / 180);

另外如评论中所述，使用好名称以避免混淆。