c++ - '字' : 'char [20]' differs in levels of indirection from 'unsigned short'

Question

我是 c++ 的新手，我收到了一个我想要运行的数据分析程序。我基本上只有一个错误要解决(在消除了数百个错误之后)，但我似乎无法破解这个错误的含义。这段代码在 Mac 上运行得很好，但我的是 Windows。我也在使用 Visual Studio。

这是发生错误的脚本。错误出现在以下行:

typedef char WORD[NWORD];

/***********************************************

 Header file with generally useful Macros

 Version for  C++

 As written here, can be included "indescriminantly"
 without danger of multiple definitions.  Nothing will
 be inserted if content has already been included.

 Program must also include stdio.h and stdlib.h, but these
 are almost universal.

 *********************************************************/

#ifndef  MCRO

#define MCRO

#define PI  3.14159265358979

#define AND     &&
#define OR      ||
#define IS      ==

#include <cstring>


#define STRCHK(x,y) if(strlen(x) >= (y)) {printf("String %s too long\n",x);exit(0);}

// This is a macro for checking reads for overrunning memory allocation
// It is a function  void STRCHK( char* x, int y) that quits program if
//  string is filled beyond its capacity y.
//  NOTE:  No ';' is needed to end line with this Macro.


#define SKIPLINE(x)   fscanf(x,"%*s%*[^\n\r][\n\r]")
// This macro skips a line in reading the file (pointer) x
// It works regardless of whether \n or\r is used for new lines

#define NWORD   20
#define NPHRASE 200

typedef char WORD[NWORD];       // Utilities for construction of arrays of strings
typedef char PHRASE[NPHRASE];

#endif

Answer 1

在 Windows 上，符号“WORD”由埋藏在 中的#define 定义[不好的做法，但历史需要向前兼容，对吧]

您需要使用除“WORD”之外的其他内容来进行您自己的定义。

这Microsoft Page将向您展示其他一些危险符号。