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java - 如何在 Java 中验证可分辨名称 (DN)?

转载 作者:行者123 更新时间:2023-11-30 03:34:35 24 4
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我正在尝试在 java 中验证 DN。到目前为止,我已尝试使用 Bouncy caSTLe 库对其进行验证

private boolean isValidDn(String dn) {
try {
X509Name name = new X509Name(dn);
return true;
} catch (IllegalArgumentException e) {

}
return false;
}

这段代码可以工作,但问题是这段代码允许有多个 CN。

例如:此代码对于 CN=first,CN=second,ou=org,ou=org2,c=US 返回 true

但我希望只有在有一个 cn、ou、o、c 等时才返回 true 的验证。

如有任何帮助,我们将不胜感激。

最佳答案

如果您使用以下枚举,您应该能够迭代 X500NameX509Name 可能的每个元素。

public enum MyBCStyle {

/**
* country code - StringType(SIZE(2))
*/
C(BCStyle.C),

/**
* organization - StringType(SIZE(1..64))
*/
O(BCStyle.O ),

/**
* organizational unit name - StringType(SIZE(1..64))
*/
OU(BCStyle.OU),

/**
* Title
*/
T(BCStyle.T ),

/**
* common name - StringType(SIZE(1..64))
*/
CN(BCStyle.CN ),

/**
* device serial number name - StringType(SIZE(1..64))
*/
SN(BCStyle.SN ),

/**
* street - StringType(SIZE(1..64))
*/
STREET(BCStyle.STREET ),

/**
* device serial number name - StringType(SIZE(1..64))
*/
SERIALNUMBER(BCStyle.SERIALNUMBER),

/**
* locality name - StringType(SIZE(1..64))
*/
L(BCStyle.L ),

/**
* state, or province name - StringType(SIZE(1..64))
*/
ST(BCStyle.ST ),

/**
* Naming attributes of type X520name
*/
SURNAME(BCStyle.SURNAME ),
GIVENNAME(BCStyle.GIVENNAME ),
INITIALS(BCStyle.INITIALS ),
GENERATION(BCStyle.GENERATION ),
UNIQUE_IDENTIFIER(BCStyle.UNIQUE_IDENTIFIER ),

/**
* businessCategory - DirectoryString(SIZE(1..128)
*/
BUSINESS_CATEGORY(BCStyle.BUSINESS_CATEGORY ),

/**
* postalCode - DirectoryString(SIZE(1..40)
*/
POSTAL_CODE(BCStyle.POSTAL_CODE ),

/**
* dnQualifier - DirectoryString(SIZE(1..64)
*/
DN_QUALIFIER(BCStyle.DN_QUALIFIER ),

/**
* RFC 3039 Pseudonym - DirectoryString(SIZE(1..64)
*/
PSEUDONYM(BCStyle.PSEUDONYM ),


/**
* RFC 3039 DateOfBirth - GeneralizedTime - YYYYMMDD000000Z
*/
DATE_OF_BIRTH(BCStyle.DATE_OF_BIRTH ),

/**
* RFC 3039 PlaceOfBirth - DirectoryString(SIZE(1..128)
*/
PLACE_OF_BIRTH(BCStyle.PLACE_OF_BIRTH ),

/**
* RFC 3039 Gender - PrintableString (SIZE(1)) -- "M", "F", "m" or "f"
*/
GENDER(BCStyle.GENDER ),

/**
* RFC 3039 CountryOfCitizenship - PrintableString (SIZE (2)) -- ISO 3166
* codes only
*/
COUNTRY_OF_CITIZENSHIP(BCStyle.COUNTRY_OF_CITIZENSHIP ),

/**
* RFC 3039 CountryOfResidence - PrintableString (SIZE (2)) -- ISO 3166
* codes only
*/
COUNTRY_OF_RESIDENCE(BCStyle.COUNTRY_OF_RESIDENCE ),


/**
* ISIS-MTT NameAtBirth - DirectoryString(SIZE(1..64)
*/
NAME_AT_BIRTH(BCStyle.NAME_AT_BIRTH ),

/**
* RFC 3039 PostalAddress - SEQUENCE SIZE (1..6) OF
* DirectoryString(SIZE(1..30))
*/
POSTAL_ADDRESS(BCStyle.POSTAL_ADDRESS ),

/**
* RFC 2256 dmdName
*/
DMD_NAME(BCStyle.DMD_NAME ),

/**
* id-at-telephoneNumber
*/
TELEPHONE_NUMBER(BCStyle.TELEPHONE_NUMBER),

/**
* id-at-name
*/
NAME(BCStyle.NAME),

/**
* Email address (RSA PKCS#9 extension) - IA5String.
* <p>Note: if you're trying to be ultra orthodox, don't use this! It shouldn't be in here.
*/
EmailAddress(BCStyle.EmailAddress),

/**
* more from PKCS#9
*/
UnstructuredName(BCStyle.UnstructuredName),
UnstructuredAddress(BCStyle.UnstructuredAddress),
E(BCStyle.E),
DC(BCStyle.DC),

/**
* LDAP User id.
*/
UID(BCStyle.UID );

private ASN1ObjectIdentifier identifier;

public ASN1ObjectIdentifier getIdentifier() {
return identifier;
}

private MyBCStyle(ASN1ObjectIdentifier asn1ObjectIdentifier) {
this.identifier = asn1ObjectIdentifier;
}
}

这样你就可以做到

for(MyBCStyle bcStyle : MyBCStyle.values()) {
if(x500name.getRDNs(bcStyle.getIdentifier()).length > 1) {
throw new IllegalArgumentException("Multiple " + bcStyle.name() + " was found.");
}
}

关于java - 如何在 Java 中验证可分辨名称 (DN)?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28294523/

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