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android - 如何在我的 Android 应用程序中使用传感器接听电话?

转载 作者:行者123 更新时间:2023-11-30 03:33:20 25 4
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我想开发一个 android 应用程序,我想在其中使用接近传感器或 ACCELEROMETER 传感器接听电话。如果有来电,当我得到一定的传感器值时,就会自动接听电话。例如,当我将我的手从左到右移动到接近传感器前面时,将接收调用,从右到左,则调用将被拒绝。在加速度计的情况下,当我用耳朵接触手机时,传感器将接收到特定的 x、y、z 值,然后将接听电话。我尝试了一些方法,但是当电话接到某个号码的电话时,我无法读取传感器值。是否有可能在 BroadCastReceiver 中获取传感器值或在电话接听电话时读取传感器?我已经从名为“Wave Control Pro”的游戏商店测试了这样一个应用程序
https://play.google.com/store/apps/details?id=com.MarksThinkTank.WaveControlPro&feature=search_result

最佳答案

像这样使用这里我得到水平和垂直的传感器

public class SensorActivity extends Activity implements SensorEventListener{
private static final String TAG="SensorActivity";

private Context context=null;
private float mLastX, mLastY, mLastZ;
private boolean mInitialized;
private SensorManager mSensorManager;
private Sensor mAccelerometer;
private final float NOISE = (float) 5.0;

ArrayList<String> arraylist=null;

private SharedPreferences seedPrefs = null;
private String prefname = "shakingvideo";

VideoBean vbean= new VideoBean();

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.video);
context=this;

mInitialized = false;
mSensorManager = (SensorManager) getSystemService(Context.SENSOR_SERVICE);
mAccelerometer = mSensorManager.getDefaultSensor(Sensor.TYPE_ACCELEROMETER);
mSensorManager.registerListener(this, mAccelerometer , SensorManager.SENSOR_DELAY_NORMAL);

arraylist= new ArrayList<String>();

}

@Override
protected void onResume() {
super.onResume();
mSensorManager.registerListener(this, mAccelerometer, SensorManager.SENSOR_DELAY_NORMAL);
}

@Override
protected void onPause() {
super.onPause();
mSensorManager.unregisterListener(this);
}


public void onAccuracyChanged(Sensor arg0, int arg1) {
// TODO Auto-generated method stub

}

public void onSensorChanged(SensorEvent event) {

float x = event.values[0];
float y = event.values[1];
float z = event.values[2];


if (!mInitialized) {
mLastX = x;
mLastY = y;
mLastZ = z;
mInitialized = true;
} else {
float deltaX = Math.abs(mLastX - x);
float deltaY = Math.abs(mLastY - y);
float deltaZ = Math.abs(mLastZ - z);
if (deltaX < NOISE) deltaX = (float)0.0;
if (deltaY < NOISE) deltaY = (float)0.0;
if (deltaZ < NOISE) deltaZ = (float)0.0;
mLastX = x;
mLastY = y;
mLastZ = z;
if (deltaX > deltaY) {


// horizontal shaking receive here your call

} else if (deltaY > deltaX) {

//Reject here your call

} else {
// no shaking
}
}
}
}

关于android - 如何在我的 Android 应用程序中使用传感器接听电话?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17036590/

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