android - 如何在 android 中单击 TextView 超链接打开 Google 页面？

Question

How to open a Google home page on click on hyperlink text view in android am trying out with following code but on click on the hyperlink it just changing to normal text how to resolve it

代码如下:

MainActivity.java(在 onCreate() 中)

instruction = (TextView) findViewById(R.id.example);

    instruction.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            instruction.setText(Html.fromHtml(getString(R.string.Google_Instructions)));
            Linkify.addLinks(instruction, Linkify.ALL);
            instruction.setMovementMethod(LinkMovementMethod.getInstance());                
        }
    });

字符串.xml

<string name="Google_Instructions">opens <a href="https://www.google.co.in">Google</a> page </string>

布局测试.xml

 <TextView
        android:id="@+id/example"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_marginTop="10sp"
        android:clickable="true"
        android:text="@string/Google_Instructions"
        android:autoLink="web"
        android:textSize="16sp" />

Answer 1

您好，我通过在 java 类中添加这一小段代码以及布局 xml 文件中的少量更改得到了解决方案

instruction = (TextView) findViewById(R.id.example);

    instruction.setText(Html
            .fromHtml("<b> To open google console </b> "
                    + "<a href=\"https://code.google.com/apis/console\">Click here</a> "));
    instruction.setMovementMethod(LinkMovementMethod.getInstance());

layout_test.xml

 <TextView
        android:id="@+id/example"
        android:layout_width="match_parent"
        android:layout_height="match_parent" />