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python - 将 Python 更改为 C++ : how to eliminate zeros that are keep appearing in vectors

转载 作者:行者123 更新时间:2023-11-30 03:28:17 25 4
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我正在尝试将此 Python 代码更改为 C++,但在我编译时不断出现不需要的零。为什么会发生这种情况,我该如何解决这个问题?

p = [0.2, 0.2, 0.2, 0.2, 0.2]
world = ['green', 'red', 'red', 'green', 'green']
measurements = ['red', 'green']
motions = [1,1]
pHit = 0.6
pMiss = 0.2
pExact = 0.8
pOvershoot = 0.1
pUndershoot = 0.1

def sense(p, Z):
q=[]
for i in range(len(p)):
hit = (Z == world[i])
q.append(p[i] * (hit * pHit + (1-hit) * pMiss))
s = sum(q)
for i in range(len(q)):
q[i] = q[i] / s
return q

def move(p, U):
q = []
for i in range(len(p)):
s = pExact * p[(i-U) % len(p)]
s = s + pOvershoot * p[(i-U-1) % len(p)]
s = s + pUndershoot * p[(i-U+1) % len(p)]
q.append(s)
return q

for k in range(len(measurements)):
p = sense(p, measurements[k])
p = move(p, motions[k])

print p

这是我的 C++ 实现代码:

#include <iostream>
#include <vector>
#include <string>
using namespace std;

vector<float> p (5);
vector<string> world (5);
vector<string> measurements (2);
vector<int> motions (2);
float pHit;
float pMiss;
float pExact;
float pOvershoot;
float pUndershoot;
vector<float> sense(vector<float> p, string Z);
vector<float> move(vector<float> p, int U);

int main(){
vector<float> p (5, 0.2);

world.push_back("green");
world.push_back("red");
world.push_back("red");
world.push_back("green");
world.push_back("green");

measurements.push_back("red");
measurements.push_back("green");

pHit = 0.6;
pMiss = 0.2;
pExact = 0.8;
pOvershoot = 0.1;
pUndershoot = 0.1;

vector<int> motions (2, 1);

for(int i=0; i<measurements.size(); i++){
p = sense(p, measurements[i]);
p = move(p, motions[i]);
}

for(int i=0; i<p.size(); i++){
cout << p[i] << " ";
}

return 0;
}

vector<float> sense(vector<float> p, string Z){
vector<float> q (p.size());
for(int i=0; i<p.size(); i++){
bool hit = (Z == world[i]);
q.push_back(p[i] * (hit * pHit + (1-hit) * pMiss));
}

float s = 0.0;
for(int i=0; i<q.size(); i++){
s += q[i];
}

for(int i=0; i<q.size(); i++){
q[i] /= s;
}

return q;
}

vector<float> move(vector<float> p, int U){
vector<float> q (p.size());
for(int i=0; i<p.size(); i++){
float s = pExact * p[(i-U) % p.size()];
s = s + pOvershoot * p[(i-U-1) % p.size()];
s = s + pUndershoot * p[(i-U+1) % p.size()];
q.push_back(s);
}
return q;
}

*期望的输出:[0.21157894736842103, 0.1515789473684211, 0.08105263157894739, 0.16842105263157897, 0.3873684210526316]

*我的输出:0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.000205128 0.00494872 0.0406154 0.119872 0.119872 0.054359 0.00994872 0.0016666667 0.016667 0.0108205 0.0108205 0.0657692 0.190641009009009009090000009009090090090009000900909090009009009009009009000909090099009090909990994940调0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 程序以退出代码结束:0

最佳答案

在 Python 意义上:

def sense(p, Z):
q=[]

您正在声明一个空列表。

但在 C++ 意义上:

vector<float> sense(vector<float> p, string Z){
vector<float> q (p.size());

您正在声明一个具有给定大小的 vector ,然后您在其上使用 push_back。这会改变大小,并在开始时留下零值。

只是做:

    vector<float> q;

然后你可以保留内存

q.reserve(p.size());

(reserve 不是resize,它在内部分配但不会改变.size())所以push_back 不需要那么多重新分配。

修复后,您可以对具有完全相同问题的 move 函数应用完全相同的修复。

关于python - 将 Python 更改为 C++ : how to eliminate zeros that are keep appearing in vectors,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46716972/

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