gpt4 book ai didi

Java:从数组列表条目中修改、搜索和删除

转载 作者:行者123 更新时间:2023-11-30 03:25:57 24 4
gpt4 key购买 nike

学习,善良。

我有一个地址簿,我需要用户能够根据他们的名字删除条目,根据他们的名字修改条目,并根据他们的名字搜索条目(你猜对了)。

我看过一些例子等,但我不知道如何做到这一点。任何帮助将不胜感激。

这是我的类文件:

import java.util.Calendar;
import java.util.Date;
import java.text.*;

public class Person implements Comparable {


private static int totalNumber;

public static int getTotal() {

//Returns total number of employees
return totalNumber;
}

private String fullName;
private String fName;
private String lName;
private Date lastModified;
private String address;
private String city;
private String state;
private String zip;
private String phone;

public Person(String fName, String lName, String address, String city, String state, String zip, String phone) {
this.fName = fName;
this.lName = lName;
this.address = address;
this.city = city;
this.state = state;
this.zip = zip;
this.phone = phone;
Calendar calobj = Calendar.getInstance();
this.lastModified = calobj.getTime();
}

public String getfullName() {
return this.fullName;
}
public void setfullName(String fullName) {
this.fullName = this.fName + this.lName;
}
public String getfName() {
return this.fName;
}

public void setfName(String fName) {
this.fName = fName;
}

public String getlName() {
return this.lName;
}

public void setlName(String lName) {
this.lName = lName;
}

public Date getLastModified() {
return this.lastModified;
}

public void setLastModified(Date lastModified) {
this.lastModified = lastModified;
}

public String getAddress() {
return this.address;
}

public void setAddress(String address) {
this.address = address;
}

public String getCity() {
return this.city;
}

public void setCity(String city) {
this.city = city;
}

public String getState() {
return this.state;
}

public void setState(String state) {
this.state = state;
}

public String getZip() {
return this.zip;
}

public void setZip(String zip) {
this.zip = zip;
}

public String getPhone() {
return this.phone;
}

public void setPhone(String phone) {
this.phone = phone;
}

@Override
public String toString() {
DateFormat df = new SimpleDateFormat("dd/MM/yy HH:mm:ss");
return "\n First Name= " + fName +
"\n Last Name= " + lName +
"\n Address= " + address +
"\n City= " + city +
"\n State= " + state +
"\n Zip= " + zip +
"\n Phone= " + phone +
"\n Last Modified= "
+ df.format(lastModified);
}

@Override
public int compareTo(Object other) {
// TODO Auto-generated method stub
return this.lName.compareToIgnoreCase(((Person) other).lName);

}








}

这是我的测试文件: 公共(public)类 testAddressBook {

    public static void main(String[] args) {
// TODO Auto-generated method stub

ArrayList<Person> addressBook = new ArrayList<Person>();
Person newPerson = new Person(null, null, null, null, null, null, null);


@SuppressWarnings("resource")
Scanner sc = new Scanner(System.in);

boolean switcher = true;
do {
System.out.println("\n\tAddress Book Menu");
System.out.println("\n\t\tEnter A to (A)dd Person ");
System.out.println("\t\tEnter D to (D)elete Person");
System.out.println("\t\tEnter M to (M)odify Person");
System.out.println("\t\tEnter S to (S)earch Address Book ");
System.out.println("\t\tEnter L to (L)ist ALL (sorted) ");
System.out.println("\t\tEnter Q to Quit");
System.out.print("\n\tPlease enter your choice: ");
char choice = sc.nextLine().toUpperCase().charAt(0);


while ((choice != 'A') && (choice != 'D') && (choice != 'M') && (choice != 'S') && (choice != 'L')&& (choice != 'Q')) {
System.out.println("Invalid choice! Please select (A)dd, (D)elete, (M)odify, (S)earch, (L)ist or (Q)uit: ");
choice = sc.nextLine().toUpperCase().charAt(0);
}


switch (choice) {
case 'A' :
System.out.println("\nTo add a person, follow the prompts.");
newPerson = new Person(null, null, null, null, null, null, null);
System.out.print("\nEnter First Name: ");
newPerson.setfName(sc.nextLine());

System.out.print("\nEnter Last Name: ");
newPerson.setlName(sc.nextLine());

System.out.print("Enter Address: ");
newPerson.setAddress(sc.nextLine());

System.out.print("Enter City: ");
newPerson.setCity(sc.nextLine());

System.out.print("Enter State: ");
newPerson.setState(sc.nextLine());

System.out.print("Enter Zip: ");
newPerson.setZip(sc.nextLine());

System.out.print("Enter Phone Number: ");
newPerson.setPhone(sc.nextLine());

addressBook.add(newPerson);

System.out.println("\nYou have successfully added a new person!");

break;

case 'D' :

break;
case 'M' :

break;
case 'S' :

System.out.println("Please enter first & last name (ex. Bob Smith): ");
String fullName = sc.nextLine();

if (addressBook.contains(fullName)) {
System.out.println("Yes, this person exists!");

} else {
System.out.println("ALERT! No record of that name exists in this address book.");
}

break;
case 'L' :
System.out.println("\nThere are " + addressBook.size() + " people in this address book.\n");
Collections.sort(addressBook);


for (int i = 0; i < addressBook.size(); i++) {
System.out.println(addressBook.get(i));


}
System.out.println();


break;
case 'Q' :
switcher = false;
System.exit(0);
break;
default:

}

}
while (switcher != false);


}
}

最佳答案

对于这里的所有内容,您必须要求用户提供一些输入,然后对该输入执行操作

删除

您可以遍历列表,也可以通过传递用户输入中的元素来获取索引。您可以使用如下所示的删除方法:-

<Your Arraylist>.remove(<Index of Element to be remove>);

修改

使用 ArrayList 的 get(index) 方法获取该特定值,然后使用 set 更新该值。

搜索

使用get方法查找它如果存在是{Do Something}如果不存在则否{Do Something}

请参阅此处的 ArrayList 方法 http://docs.oracle.com/javase/7/docs/api/java/util/ArrayList.html

关于Java:从数组列表条目中修改、搜索和删除,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30221474/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com